Question

Angle FEDwith angleF=90degree, ED=36, and FE=22, calcularé the measures of the unknown angles and the unknown side length of the triangle. Round your measures to the nearest tenth of a degree

Answer 1

Answer:

$\angle D=37.7^{\circ}$

$\angle E=52.3^{\circ}$

$FD\approx 28.5$

Step-by-step explanation:

Please find the attachment.

We have been given that angle FED with angle F=90 degree, ED=36, and FE=22. We are asked to find the unknown angles and the unknown side length of the triangle.

We will use sine to solve for angle D as:

$\text{sin}=\frac{\text{Opposite}}{\text{Hypotenuse}}$

$\text{sin}(D)=\frac{22}{36}$

$D=\text{sin}^{-1}(\frac{22}{36})$

$D=37.66988696^{\circ}$

$D\approx 37.7^{\circ}$

Therefore, measure of angle D is 37.7 degrees.

Now, we will find measure of angle E using angle sum property.

$m\angle E+m\angle F+m\angle D=180^{\circ}$

$m\angle E+90^{\circ}+37.7^{\circ}=180^{\circ}$

$m\angle E+127.7^{\circ}=180^{\circ}$

$m\angle E+127.7^{\circ}-127.7^{\circ}=180^{\circ}-127.7^{\circ}$

$m\angle E=52.3^{\circ}$

Therefore, measure of angle E is 52.3 degrees.

We will use Pythagoras theorem to solve for side FD as:

$FD^2+EF^2=ED^2$

$FD^2+22^2=36^2$

$FD^2+484=1296$

$FD^2=1296-484$

$FD^2=812$

$FD=\sqrt{812}$

$FD=28.495613697\\\\FD\approx 28.5$

Therefore, length of side FD is approximately 28.5 units.