Remember a^(m) x a^(n) = a(m+n) & √a = a^(1/2)
===> x^(1/2 -3/2)+x(1/2 -1/2) ====> x^(-1)+x^(0) (any number Exp 0 =1)
X^(-1) +1 ===> 1/x +1 or (1+x)/x
Answer:
n=601
Step-by-step explanation:
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The population proportion have the following distribution
In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by
and
. And the critical value would be given by:
The confidence interval for the mean is given by the following formula:
The margin of error for the proportion interval is given by this formula:
(a)
And on this case we have that
and we are interested in order to find the value of n, if we solve n from equation (a) we got:
(b)
Since we don't have a prior estimation for the proportion we can use 0.5 as estimation. And replacing into equation (b) the values from part a we got:
And rounded up we have that n=601
<span>=<span><span><span><span>(8)</span><span>(4)</span></span>−4</span>+5
</span></span><span>=<span><span>32−4</span>+5
</span></span><span>=<span>28+5
</span></span><span>=<span>33</span></span>
Answer:
0.1
Step-by-step explanation:
r = y/x
r = 1.4 / 14 = 0.1
Answer:
3003 different groups of 6tops
Step-by-step explanation:
Using the combination formula, generally, when selecting r number of objects out of a pool of n numbers, this can be done in nCr number of ways.
nCr = n!/(n-r)!r!
If there are 14 tops I'd like to purchase and I can only afford six, the number of ways I can choose this six at random from the 14tops can be done in 14C6 number of ways.
14C6 = 14!/(14-6)!6!
14C6 = 14!/8!6!
14C6 = 14×13×12×11×10×9×8!/8!×6×5×4×3×2
14C6 = 14×13×12×11×10×9/6×5×4×3×2
14C6 = 14×13×12×11/8
14C6 = 3003ways