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const2013 [10]
3 years ago
15

A population of 1,750 cheetahs decreases by 11% per year. How many cheetahs will there be in the population after 10 years?

Mathematics
2 answers:
Sever21 [200]3 years ago
7 0
First, write an equation.

1750 = number of cheetahs
.89 = Rate (1-.11)
x = Number of years

1750(.89)^x

1750(.89)^10 = 545.68 (you cant have half a cheetah) so around 546
Cerrena [4.2K]3 years ago
3 0
It would be a population of 546 cheetahs 
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-6 3/5 - (-7 4/15) + 2 1/5
Ilya [14]

Answer:2.87

Step-by-step explanation:

3 0
3 years ago
I need help with this question asap
guajiro [1.7K]
((2t+10) / 2) + ((3t-15) / 2) + (3s) = 180 
((2t+10) / 2) + ((3t-15) / 2) + (4r) = 180
((2t+10) / 2) + ((3t-15) / 2) + (3s) = ((2t+10) / 2) + ((3t-15) / 2) + (4r) 
(2t+10) = (3t-15)   t=25
2*25+10= 60  ,   3*25-15=60
60+60= 120 ,   This rectangle has a total of 360 degrees 
360 - 120 = 240
240/2 =120
120/ 4 = 30  ,  120/3 = 40
r=30    s=40

6 0
3 years ago
Simone paid $12 for an initial years subscription to a magizine. The renewal rate is $8 per year. This situation can be represen
Y_Kistochka [10]
This is easy. Select different values for x to find y values.

For example, let x = 0.

y = 8x + 12

y = 8(0) + 12

y = 0 + 12

y = 12

On your table, you have x = 0 and y = 12.

Do the same using other values of x.
5 0
3 years ago
I’m confused and don’t have an angle tool to even try to do the question
yanalaym [24]
<h3>Answer:   40</h3>

=================================================

Explanation:

JQ is longer than QN. We can see this visually, but the rule for something like this is the segment from the vertex to the centroid is longer compared to the segment that spans from the centroid to the midpoint.

See the diagram below.

The ratio of these two lengths is 2:1, meaning that JQ is twice as long compared to QN. This is one property of the segments that form when we construct the centroid (recall that the centroid is the intersection of the medians)

We know that JN = 60

Let x = JQ and y = QN

The ratio of x to y is x/y and this is 2/1

x/y = 2/1

1*x = y*2

x = 2y

Now use the segment addition postulate

JQ + QN = JN

x + y = 60

2y + y = 60

3y = 60

y = 60/3

y = 20

QN = 20

JQ = 2*y = 2*QN = 2*20 = 40

--------------

We have

JQ = 40 and QN = 20

We see that JQ is twice as larger as QN and that JQ + QN is equal to 60.

7 0
3 years ago
A batch consists of 12 defective coils and 88 good ones. Find the probability of getting two good coils when two coils are rando
Nastasia [14]

Answer:

The probability of getting two good coils is 77.33%.

Step-by-step explanation:

Since a batch consists of 12 defective coils and 88 good ones, to determine the probability of getting two good coils when two coils are randomly selected (without replacement), the following calculation must be performed:

88/100 x 87/99 = X

0.88 x 0.878787 = X

0.77333 = X

Therefore, the probability of getting two good coils is 77.33%.

7 0
2 years ago
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