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2 years ago

A population of 1,750 cheetahs decreases by 11% per year. How many cheetahs will there be in the population after 10 years?

2 answers:

7 0

First, write an equation.

1750 = number of cheetahs
.89 = Rate (1-.11)
x = Number of years

1750(.89)^x

1750(.89)^10 = 545.68 (you cant have half a cheetah) so around 546

Cerrena [4.2K]2 years ago

3 0

It would be a population of 546 cheetahs

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73.

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Since we can't divide by zero, we need to find when:

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But before, we can factor the numerator and the denominator:

$\begin{gathered} \frac{3x^2(x^2+x-12)}{x^4-25x^2+144}=\frac{3x^2((x+4)(x-3))}{(x-3)(x-3)(x+4)(x+4)} \\ so: \\ \frac{3x^2}{(x+3)(x-4)} \end{gathered}$

Now, we can conclude that the vertical asymptotes are located at:

$\begin{gathered} (x+3)(x-4)=0 \\ so: \\ x=-3 \\ x=4 \end{gathered}$

so, for x = -3:

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For x = 4:

$\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty$ $\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty$

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Step-by-step explanation:

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Step-by-step explanation:

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