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Eduardwww [97]
3 years ago
8

09-7.5 Help with math

Mathematics
1 answer:
lisov135 [29]3 years ago
7 0

Answer: the answer to this equation is 1.5

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Determine o x 2x+15 3x-25
Papessa [141]
2x+15 = 3x-25
2x-3x = -25 -15
-x = -40
x = 40
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2 years ago
What’s is the area of shape B?
Phantasy [73]

Answer:

28.5 cm²

Step-by-step explanation:

There are 7 whole diamonds and 5 half-diamonds.  Each diamond is worth three.

7x3=21

5/2x3=7.5

21+7.5=28.5

6 0
2 years ago
Read 2 more answers
-5x - 7 < 28
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-5x - 7 < 28.....add 7 to both sides
-5x < 35....divide both sides by -5, change the inequality sign (u change the inequality sign when dividing/multiplying by a negative number)
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3 years ago
Joe is 1.6 m tall. His shadow is 2 m long when he stands 3 m
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Answer:

Step-by-step explanation:

6 0
1 year ago
Find the area of the shaded regions below. Give your answer as a completely simplified exact value in terms of π (no approximati
Y_Kistochka [10]

Hello from MrBillDoesMath!

Answer:   8 (Pi - sqrt(3))

Discussion:

The area of the shaded region is that of the semicircle minus the area of the triangle..


Area of semicircle = 1/2 * Pi * R^2        

    Where R^2 is the square of the radius of the circle. In our case, R ( = OC)

     = 4 so the semicircle area is

    (1/2) * Pi * (4^2) = (1/2) * Pi * 16 = 8 Pi


Area of triangle.

   First of all, angle ACB is a right angle ( i.e. 90 degrees).

     * This is the Theorem of Thales from elementary Plane Geometry. *

  so by Pythagoras

    AC^2 + BC^2 = AB^2

 But CB = 4 (given) and AB = 4*2 = 8 ( the diameter is twice the radius).

 Substituting these in Pythagoras gives

    AC^2 + 4^2 = 8^2 or

    AC^2 = 8^2 - 4^2- = 64 - 16 = 48

    Hence AC = sqrt(48) = sqrt (16*3) = 4 * sqrt(3)

We are almost done! The area of the triangle is given by

   (1/2) b * h = (1/2)  BC * AC = (1/2) 4 * (4 * sqrt(3)) =  8 sqrt(3)

We conclude the area area of the shaded part is

  8 PI - 8 sqrt(3)   = 8 (Pi - sqrt(3))

Note that sqrt(3) is approx  1.7 so (PI - sqrt(3)) is a positive number, as it better well be!


Thank you,

MrB

6 0
3 years ago
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