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2 years ago

Which decimal is larger?? .77 or .775?

2 answers:

6 0

Simply multiply both decimals with 1000 for comparison.

$0.77X 1000 = 770\\\\0.775 X 1000 = 775\\\\Its\ clear\ that\ 0.775\ is\ greater\ than\ 0.77$

Butoxors [25]2 years ago

6 0

.775 is larger

Think like: is .70 or .75 bigger
It would be .75 because 75 is bigger than 70

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What is the value of x?<br><br>enter your answer in the box<br><br>X__

vfiekz [6]

<h3>Answer: x = 5</h3>

=====================

Work Shown:

Angle Bisector Theorem

9/(2x-1) = 15/3x

9*3x = 15(2x-1) ... cross multiply

27x = 30x-15

27-30x = 30x-15-30x ... subtract 30x from both sides

-3x = -15

-3x/(-3) = -15/(-3) .... divide both sides by -3

x = 5

6 0

2 years ago

Pwese help ill give brainlyest

Luda [366]

Answer:

y=(14-8x) divided by 2

Step-by-step explanation:

minus 8x from both side you get

2y=14-8x

then you divide by 2

y=(14-8x) divided by 2

thats the furthest it can be simplified

4 0

2 years ago

Read 2 more answers

If a car can drive 62 miles on 3 gallons of gas, how many gallons of gas will it use to travel 231 miles?

aksik [14]

Answer:

11 gallons of gas is needed to travel 231 miles.

Step-by-step explanation:

We can set up a proportion for this problem.

<em>For every 62 miles, you use 3 gallons of gas. </em>

$\frac{62}{3}*\frac{231}{?}$

Now, let's cross multiply.

$\frac{693}{62}$ ≈ $11$

So, you will need about 11 gallons of gas to travel 231 miles.

8 0

2 years ago

Write the recurring decimal 0.5 as a fraction in its simplest form.

sergejj [24]

Answer:

0.5×2/2=1/2 is the required fraction.

8 0

2 years ago

Read 2 more answers

In the game of roulette, a player can place a $8 bet on the number 17 and have a StartFraction 1 Over 38 EndFraction probabili

svp [43]

Answer:

Expected value of the game: -$0.421

Expected loss in 1000 games: $421

Step-by-step explanation:

There are two possible outcomes for the event:

- There is a 1 in 38 chance of winning $280

- There is a 37 in 38 chance of losing $8

The expected value for a single game is:

$E(X) = \frac{1}{38}*\$280-\frac{37}{38}*\$8\\E(X)=-\$0.421$

The expected value of the game is -$0.421

In 1,000 plays, the expected loss is:

$L = 1,000*-\$0.421\\L=-\$421$

You would expect to lose $421.

3 0

2 years ago