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3 years ago

What is the answer to this question

Biology

2 answers:

Zielflug [23.3K]3 years ago

7 0

If the width is increased it would be harder to stretch more force will be needed to stretch it

Dafna11 [192]3 years ago

6 0

Answer:

Explanation:

you already told me that

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What kind of traits do brown beetle have

marin [14]

Head,Thorax,abdomen and six legs

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2 years ago

Some protozoans have special organelles called contractile vacuoles that continually eliminate excess water from the cell. The p

Ann [662]

Answer:

Liquid and with a higher osmotic pressure

Explanation:

Remember that a cell that is surrounded by an environment with a higher osmotic pressure, will produce that the cell get some water outside to make some dilution to the salt concentration that surrounds the protozoan.

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3 years ago

All that apply

Alexxandr [17]

Yeast has many comercial uses in the production of breads, fuel, sodas, and wine.

7 0

3 years ago

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Alleles are:

Marianna [84]

Answer:

Alternate form of gene

Explanation:

An allele is a variant form of a gene. Some genes have a variety of different forms, which are located at the same position, or genetic locus, on a chromosome. Humans are called diploid organisms because they have two alleles at each genetic locus, with one allele inherited from each parent.

6 0

3 years ago

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In maize, liguleless (l) is recessive to having ligules (L), and dwarf (d) is recessive to tall (D). These two genes are linked

bearhunter [10]

Answer:

given,

LL║ll and DD║dd,

after crossing over, Ld║Ld × lD║lD

LLdd × llDD

in F1 generation, they will give, LLll, DDdd, LLDD, lldd → LlDd

in eF2 generation, the offsprings will be, LLll × DDdd

LLDD ,LLdd, LLDd, llDD, lldd, llDd, LlDD, Lldd, LlDd

1. yes, these genes are coupling.

2. → phenotypes of parental genes = ligules, liguleless, tall and dwarf

genotypes of parental genes= LLdd, llDD i.e; heterozygous

→ phenotypes of F1 generation = 25% Ligules, 25% tall, 25% ligules-tall, 25% liguleless-dwarf

genotypes of F1 generation = heterozygous ; LlDd that is ligules-tall

3. recombination frequency= no of recombinant / total progeny × 100%

= (1344+1344) / 6156+1344+1344+1156 × 100%

= 2688/ 10000 × 100%

= 26.88 %

that means linkage happened

and the map distance is 26.88 map unit.

8 0

3 years ago