Question

Events D and E are independent, with P(D)- 0.6 and P(D and E) - 0.18. Which of the following is true? A. P(E)- 0.12 B. P(E) = 0.4 C. P(D or E)-0.28 D. P(D or E) 0.72 E. P(D or E)-0.9 16, Mr. Steckler travels through two intersections with traffic lights as he drives to the mercado. The traffic lights operate independently. The probability that both lights will be red when he reaches them is 0.22 the probability that the first light will be red and the second light will not be red is 0.33. What is the probability that the second light will be red when he reaches it? A. 0.40 B, 0.45 C. 0.50 D. 0.55 E. 0.60

Answer 1

Answer:

Step-by-step explanation:

Given that Events D and E are independent, with P(D)- 0.6 and P(D and E) - 0.18.

P(D and E) = P(D)*P(E) (since independent)

Or P(E) = 0.3

Using this we find

P(Dor E) = $0.6+0.3-0.18 =0.72$

QNo2

Since lights are independent

P(Both) = P(A) *P(B) =0.22 where A I light on and B second light on

P(AB') = P(A) P(B') = 0.33

When we add we get P(A) = 0.55

P(B) = $\frac{P(AB)}{P(A)} =0.6$

the probability that the second light will be red when he reaches it

= P(B) = 0.60