Play usually continues 7.Qf3+ Ke6 8.Nc3 (see diagram). Black will play 8...Nb4 or 8...Ne7 and follow up with c6, bolstering his pinned knight on d5. If Black plays 8...Nb4, White can force the b4 knight to abandon protection of the d5 knight with 9.a3?! Nxc2+ 10.Kd1 Nxa1 11.Nxd5, sacrificing a rook, but current analysis suggests that the alternatives 9.Qe4, 9.Bb3 and 9.O-O are stronger. White has a strong attack, but it has not been proven yet to be decisive.
Because defence is harder to play than attack in this variation when given short time limits, the Fried Liver is dangerous for Black in over-the-board play, if using a short time control. It is also especially effective against weaker players who may not be able to find the correct defences. Sometimes Black invites White to play the Fried Liver Attack in correspondence chess or in over-the-board games with longer time limits (or no time limit), as the relaxed pace affords Black a better opportunity to refute the White sacrifice.
Answer:
The smallest value of p+q is 11
It happens when p = 6 and q = 5.
=======================================================
Explanation:
Let's factor 180 in such a way that exactly one factor is a perfect square.
I'll ignore the trivial factor of 1.
Here are the possible factorizations we could go with:
180 = 4*45
180 = 9*20
180 = 36*5
Those factorizations then lead to the following
Then we have
p+q = 2+45 = 47
p+q = 3+20 = 23
p+q = 6+5 = 11
The smallest value of p+q is 11 and it happens when p = 6 and q = 5.
Side note: p+q is smallest when we go with the largest perfect square factor.
Answer:
y = 5
Step-by-step explanation:
WY is the perpendicular bisector of XZ and so divides ΔWXZ into 2 congruent triangles ΔWXY and ΔWZY
Hence WZ = WX ← corresponding sides, thus
5y - 8 = 2y + 7 ( subtract 2y from both sides )
3y - 8 = 7 ( add 8 to both sides )
3y = 15 ( divide both sides by 3 )
y = 5
Answer:
Step-by-step explanation:
7w+w-15=17
8w=17+15 add like terms
8w=32 divide
w=32/8=4
now check
7*4+4-15=17
28+4-15=17
17=17
You need to make this easier to understand. <span />
