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2 years ago

6

For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 80 N acts on

a certain object, the acceleration of the object is 10 m/s2. If the force is changed to 24 N, what will be the acceleration of the object?

1 answer:

FinnZ [79.3K]2 years ago

3 0

745

because if you add the 300 and subtract it again then you will get 745

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Surface area of this figure

tamaranim1 [39]

Answer:

23

Step-by-step explanation:

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4 0

3 years ago

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use Taylor's Theorem with integral remainder and the mean-value theorem for integrals to deduce Taylor's Theorem with lagrange r

Vadim26 [7]

Answer:

As consequence of the Taylor theorem with integral remainder we have that

$f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \int^a_x f^{(n+1)}(t)\frac{(x-t)^n}{n!}dt$

If we ask that $f$ has continuous $(n+1)$ th derivative we can apply the mean value theorem for integrals. Then, there exists $c$ between $a$ and $x$ such that

$\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}dt = \frac{f^{(n+1)}(c)}{n!} \int^a_x (x-t)^n d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{n+1}}{n+1}\Big|_a^x$

Hence,

$\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{(n+1)}}{n+1} = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1} .$

Thus,

$\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}$

and the Taylor theorem with Lagrange remainder is

$f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}$ .

Step-by-step explanation:

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3 years ago

Express in simplest form with a rational denominator.<br> 4 over 28

aleksandr82 [10.1K]

Answer:

Explained in detail below

Step-by-step explanation:

4/28 = 1/7 = 1:7

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3 years ago

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~~~°°Solve 15x+2=17~~~°°

Step2247 [10]

Simple...

you have: 15x+2=17

Isolate the variable (x)-->>>>

15x+2=17
-2 -2

15x=15

x=1

To check it-->>>

15(1)+2=17

17=17

Thus, your answer.

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3 years ago

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Solve the problem. The formula d = rt gives the distance traveled in time t at rate r. If a bicyclist rides for 2.3 hours and tr

Contact [7]

Answer:

17.83

Step-by-step explanation:

d = r*t

d = 41 miles

t = 2.3 hours

r = ??

d = rt Substitute

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41 / 2.3 = r Switch sides

r = 41/2.3

r = 17.83 mph Answer

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3 years ago