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4 years ago

24 + 9 as a product using gcf

Mathematics

2 answers:

Semmy [17]4 years ago

7 0

I believe the answer to be 3

Dmitrij [34]4 years ago

6 0

The answer is intact 3 because the last number of gcf oh 9 is 3•3 and that is the greatest so 24 it goes into 3 so the greatest common factor is 3

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Which sum is equal to the expression - 5x3 + 2x2 + 9x+2/<br> (x²+ 2)²

Makovka662 [10]

Answer:

Option C

Step-by-step explanation:

Given expression is $\frac{-5x^3+2x^2+9x+2}{(x^2+2)^2}$

Option A

$\frac{A}{x^2+2}+ \frac{Bx+C}{(x^2+2)^2}$

= $\frac{A(x^2+2)}{(x^2+2)^2}+ \frac{Bx+C}{(x^2+2)^2}$

= $\frac{Ax^2+2A+Bx+C}{(x^2+2)^2}$

Numerator is a quadratic polynomial, while the expression has the numerator as a cubic .

Therefore, both the expressions are not equivalent.

Option B

$\frac{A}{(x^2+2)^2}+ \frac{Bx+C}{(x^2+2)^2}$

= $\frac{A+Bx+C}{(x^2+2)^2}$

Here, numerator of the expression is a linear polynomial which is not equal to given expression.

Therefore, both the expressions are not equivalent.

Option C

$\frac{Ax+B}{(x^2+2)}+ \frac{Cx+D}{(x^2+2)^2}$

= $\frac{(Ax+B)(x^2+2)}{(x^2+2)^2}+ \frac{Cx+D}{(x^2+2)^2}$

= $\frac{Ax^3+Bx^2+2Ax+2B+Cx+D}{(x^2+2)^2}$

= $\frac{Ax^3+Bx^2+x(2A+C)+D}{(x^2+2)^2}$

Here, numerator is a cubic polynomial.

Therefore, both the expressions are equivalent.

Option D

$\frac{Ax+B}{(x^2+2)^2}+ \frac{Cx+D}{(x^2+2)^2}$

= $\frac{x(A+C)+(B+D)}{(x^2+2)^2}$

Numerator is a linear polynomial.

Therefore, sum is not equal to the given expression.

Option C will be the answer.

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Your answer is 14.

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