Answer:
Perimeter: 4 * s
Area: S 2
Diagonal: s 2 \sqrt {2} 2
Area of square when diagonal is given = 1 2 × d 2 \frac {1} {2}\times d^ {2} 21 × d2
Step-by-step explanation:
Answer:
y-(-1)=2/3(x-5)
Step-by-step explanation:
Point slope form is
y-y_1=m(x-x_1) where m is the slope, x_1 is the x coordinate of a point that the line passes through, and y_1 is the y coordinate of a point the line passes through.
Substituting, we get
y-(-1)=2/3(x-5)
Answer:
Step-by-step explanation:
<u>Equation of a Circle</u>
A circle of radius r and centered on the point (h,k) can be expressed by the equation
We are given the equation of a circle as
Note we have corrected it by adding the square to the y. Simplify by 3
Complete squares and rearrange:
We can see that, if r=4, then
Or, equivalently
There are two solutions for :
Keeping the positive solution, as required:
These lines are perpendicular!
y = x
y = -x–2
The slopes are reciprocals of each other, so they are perpendicular.
What does the spaces in between the numbers mean