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Diano4ka-milaya [45]
4 years ago
14

1. Find the value of x in the figure below.

Mathematics
2 answers:
bagirrra123 [75]4 years ago
7 0

Answer:

see details and attached figure below.

Step-by-step explanation:

Going row by row

1. 12  (isosceles triangles have equal legs from the vertex)

2. 55 deg. (isosceles triangles have equal base angles)

3. 90 = 180-45-45 (isosceles triangles have equal base angles)

4. 2x-8 = 10

=> x = 18/2 = 9 (isosceles triangles have equal legs from the vertex)

5. sum of angles of triangle = 180

3x+3x+2x+4 = 180 => 8x = 176, x = 22, angle A = 3x = 66 deg.

6. sum of angles of triangle = 180

(isosceles triangles have equal base angles)

25+25+angle Z = 180 => angle Z = 180-25-25 = 130

Alina [70]4 years ago
7 0
Your answer would be 130
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-4+6x=2 I don’t understand how to solve it
coldgirl [10]

Answer:

x=1

Step-by-step explanation:

-4+6x=2

6x=2-(-4)

6x=2+4

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3 years ago
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Andre says 10x + 6 and 5x + 11 are equivalent because they both equal 16 when x is 1. Do you agree with Andre?​
Serga [27]

Answer:

No, They are not equivalent

Step-by-step explanation:

The two expressions are only said to be equivalent if they are the same regardless of whatever value the variable(s) is.

The variable in this question is x.

To prove this, we equate both expressions:

10x + 6 = 5x + 11

10x - 5x = 11 - 6\\\\\\5x = 5\\\\\\x = 1

This shows that they have the same value ONLY when x is 1.

This is why Andre says that they are equivalent, but they are not.

8 0
3 years ago
A department store will place a sale item in a special display for a one-day sale. Previous experience suggests that 43 percent
Svetradugi [14.3K]

Answer:

672.7436 units of the sale item should the store stock in order to have at most a 1 percent chance of running short of the item on the day of the sale

Step-by-step explanation:

No. of customers pass the display on the day of sale = 1462

Proportion of people will purchase if pass such a special display = 0.43

Mean = E(X)=np

E(X)=1462 \times 0.43

E(X)=628.66

Standard deviation = \sqrt{npq}

Standard deviation =\sqrt{1462 \times 0.43 \times (1-0.43)}=18.92

Now we are supposed to find how many units of the sale item should the store stock in order to have at most a 1 percent chance of running short of the item on the day of the sale

P(X<x)=0.01

Using z table

P(\frac{x-\mu}{\sigma})= 2.33 \\\frac{x-628.66}{18.92}=2.33\\x=(2.33 \times 18.92)+628.66\\x=672.7436

Hence 672.7436 units of the sale item should the store stock in order to have at most a 1 percent chance of running short of the item on the day of the sale

5 0
3 years ago
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