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statuscvo [17]
3 years ago
15

And evaluate x(- y + z) for x=-1 y=-2 and z=5

Mathematics
2 answers:
alukav5142 [94]3 years ago
6 0

Put the values of x, y and z to the expression.

(-1)(-(-2)+5)=(-1)(2+5)=(-1)(7)=-7

Used PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

IRISSAK [1]3 years ago
5 0
Multiply x to (-y) then x to (z)
mean x(-y)+ x(z)
plug in the variable given
(-1)(-(-2)+5)
-2-5=-7
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<span>M can have a coordinate of (-9) or (1) There are potentially 3 different places for point M to go. It can be placed to the left of point A, between points A and B, and to the right of point B. Let's check those three possibilities. 1. Left of point A. This works if the distance between M and A is the same as the distance between A and B. So distance between A and B = 6 - (-1.5) = 6 + 1.5 = 7.5 So the location for M would be -1.5 - 7.5 = -9 So point M can have the value of -9. 2. Between A and B. This would also work. Since we want a 1:2 ratio, place M one third of the way from A to B. Since we already know the distance between A and B to be 7.5, that means that we should add 7.5/3 = 2.5 to the value of A. So -1.5 + 2.5 = 1 So point M can also have the value of 1. 3. To the right of point B This won't work. Point B will always be closer to M than point A will be. So it's impossible to get a ratio of 1:2.</span>
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Answer:

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Step-by-step explanation:

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3 0
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4 (1/2x 7) = 12. what is x. can someone do the whole answer with the work?
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3 years ago
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Your friend says that the absolute value equation |3x+8|−9=−5 has no solution because the constant on the right side of the equa
xenn [34]

Solution, solve\:for\:x,\:\left|3x+8\right|-9=-5\quad :\quad x=-4\quad \mathrm{or}\quad \:x=-\frac{4}{3}

Steps:

\left|3x+8\right|-9=-5

\mathrm{Add\:}9\mathrm{\:to\:both\:sides},\\\left|3x+8\right|-9+9=-5+9

\mathrm{Simplify},\\\left|3x+8\right|=4

|f\left(x\right)|=a\quad \Rightarrow \:f\left(x\right)=-a\quad \mathrm{or}\quad \:f\left(x\right)=a,\\3x+8=-4\quad \quad \mathrm{or}\quad \:\quad \:3x+8=4

3x+8=-4,\\\mathrm{Subtract\:}8\mathrm{\:from\:both\:sides},\\3x+8-8=-4-8,\\\mathrm{Simplify},\\3x=-12,\\\mathrm{Divide\:both\:sides\:by\:}3,\\\frac{3x}{3}=\frac{-12}{3},\\\mathrm{Simplify},\\x=-4

3x+8=4,\\\mathrm{Subtract\:}8\mathrm{\:from\:both\:sides},\\3x+8-8=4-8,\\\mathrm{Simplify},\\3x=-4,\\\mathrm{Divide\:both\:sides\:by\:}3,\\\frac{3x}{3}=\frac{-4}{3},\\\mathrm{Simplify},\\x=-\frac{4}{3}

Combine\:the\:ranges,\\x=-4\quad \mathrm{or}\quad \:x=-\frac{4}{3}

\mathrm{The\:Correct\:Answer\:is\:No\:They\:Are\:Not\:Correct}

\mathrm{Hope\:This\:Helps!!!}

\mathrm{-Austint1414}

4 0
2 years ago
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