Answer:
The area of △AON and the area of △ABC is x. The area of △AON is one-sixth part of △ABC.
Step-by-step explanation:
Let the total area of △ABC be x.
A median of a triangle divides the area of a triangle in two equal parts.
Since AM are CN are medians, therefore the area of △ACN, △BCN, △ABM and △ATM are equal, i.e., .
A centroid is the intersection point of all medians of a triangle. A centroid divides each median in 2:1.
Since CN is median and O is the centroid of the triangle, therefore CO:ON is 2:1.
Draw a perpendicular on CN from A as shown in below figure. Let the height of the pendicular on CN from A be h.
Therefore the area of △AON is one-third of △ACN.
The area of ANO is . Therefore the area of △AON is one-sixth part of △ABC.
Answer:
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Step-by-step explanation:
Answer:
Step-by-step explanation:
15 + c² = 96
c² = 96 - 15
c² = 81
c² = 9²
c = 9