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larisa [96]
3 years ago
11

Find the probability a random voltage is between 124.1 volts and 124.7 volts.

Mathematics
1 answer:
Mandarinka [93]3 years ago
8 0

Answer:

C. 0.30

The probability is 0.30

Step-by-step explanation:

The diagram used in solving this question is attached.

From the given graph that is attached: the needed region have

height = 0.5

width = 124.7 - 124.1 = 0.6

The area of the rectangular region is:

= l * b\\= 0.6 * 0.5\\= 0.3

Therefore, the probability of a random voltage between 124.1 and 124.7 is 0.3

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I need help again I’m pretty stuck
ANEK [815]

Answer:

1: 45

3: 45

4: 135

5: 103

6: 77

8: 77

9: 135

10: 45

11: 135

12: 45

13: 77

14: 103

15: 77

16: 103

Step-by-step explanation:

6 0
2 years ago
How many ways can eight letters be arranged into groups of five where order matters and the first two letters are already chosen
fenix001 [56]

Answer:

120

Step-by-step explanation:

Since we're dealing with a problem where the order matters and the first two letters are already chosen we need to subtract the number of letters and the number of available slots per group.

We use the permutation formula to find the answer, but before that let's check values.

n = 8

k = 5

Now since there are two letters already chosen we have to deduct two from both the value of n and k.

n = 6

k = 3

Now we can use the permutation formula:

_{n}P_{k}=\dfrac{n!}{(n-k)!}

_{6}P_{3}=\dfrac{6!}{6-3)!}

_{6}P_{3}=\dfrac{6!}{3!}

_{6}P_{3}=\dfrac{6*5*4*3*2*1}{3*2*1}

The 3*2*1 cancels out and leaves us with:

_{6}P_{3}=6*5*4

_{6}P_{3}=120

So there are 120 possible ways to arrange eight letters into groups of five where order matters and the first two letters are already chosen.

6 0
3 years ago
Read 2 more answers
Which of the following arithmetic sequences have a common difference of ? -4,-1.5,1,3.5,6,8.5 1.5,3,4.5,6,7.5
zavuch27 [327]
F(x+1) = f(x) + 2.5 with f(x) is the current number.
7 0
3 years ago
Is 12.56 bigger than 125.6
VARVARA [1.3K]
No it's smaller. 12.56 is much less than 125.6.

5 0
3 years ago
Please help STRUGGLING with math few math questions! Ty
-BARSIC- [3]

Question 1:


F(x) and g(x) are like variables, just plug into the equation.


f(x) + g(x) = (x + 6) + (12x - 7)


x+6+12x-7 = 13x-1


Question 2: f(3) + g(-1)


You plug in the x-values into the equation, and then take the answer and add them together.


f(3) = 3+4

g(-1) = 12(-1)-6


f(3) = 7

g(-1) = -18


7 + (-18) = -11


Question 3:


This is similar to question 1, plug in the variables and simplify.


9x - (7x+3)


Remember to distribute the "-"


9x - 7x - 3

2x - 3

6 0
3 years ago
Read 2 more answers
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