Answer:
1: 45
3: 45
4: 135
5: 103
6: 77
8: 77
9: 135
10: 45
11: 135
12: 45
13: 77
14: 103
15: 77
16: 103
Step-by-step explanation:
Answer:
120
Step-by-step explanation:
Since we're dealing with a problem where the order matters and the first two letters are already chosen we need to subtract the number of letters and the number of available slots per group.
We use the permutation formula to find the answer, but before that let's check values.
n = 8
k = 5
Now since there are two letters already chosen we have to deduct two from both the value of n and k.
n = 6
k = 3
Now we can use the permutation formula:




The 3*2*1 cancels out and leaves us with:


So there are 120 possible ways to arrange eight letters into groups of five where order matters and the first two letters are already chosen.
F(x+1) = f(x) + 2.5 with f(x) is the current number.
No it's smaller. 12.56 is much less than 125.6.
Question 1:
F(x) and g(x) are like variables, just plug into the equation.
f(x) + g(x) = (x + 6) + (12x - 7)
x+6+12x-7 = 13x-1
Question 2: f(3) + g(-1)
You plug in the x-values into the equation, and then take the answer and add them together.
f(3) = 3+4
g(-1) = 12(-1)-6
f(3) = 7
g(-1) = -18
7 + (-18) = -11
Question 3:
This is similar to question 1, plug in the variables and simplify.
9x - (7x+3)
Remember to distribute the "-"
9x - 7x - 3
2x - 3