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faltersainse [42]
3 years ago
13

A confidence level of 95% mean

Mathematics
2 answers:
USPshnik [31]3 years ago
8 0

Answer:

A 95% confidence interval is a range of values that you can be 95% certain contains the true mean of the population. ... The 95% confidence interval defines a range of values that you can be 95% certain contains the population mean.

Step-by-step explanation:

hope that helps

zysi [14]3 years ago
8 0

Answer:

B. 95% of the time, population data will fall between 149.61 and 150.39.

Step-by-step explanation:

i got it right on edge

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Is the data set approximately periodic? If so, what are its period and amplitude?
Allushta [10]

Considering the given table and the periodicity concept, it is found that the data set is not periodic.

<h3>What is the period of a data-set?</h3>

The period of a function is given by the <u>distance between it's repetitions</u>.

An example of a periodic data-set with a period of 3 would be 1,2,3,1,2,3,1,2,3,...

In this problem, looking at the table, it is found that there are no patterns of repetitions, that is, the number of cars washed do not follow a repeated pattern, hence the data set is not periodic.

More can be learned about the period of a data-set at brainly.com/question/27322869

6 0
3 years ago
Kevin is 3 times as old as Daniel. 4 years ago, Kevin was 5 times as old as Daniel.
rusak2 [61]

Answer:

24

Step-by-step explanation:

4 years ago, Daniel would've been 4 and Kevin would be 20, so Kevin would've been 5 times as old as Daniel. And 8 x 3 = 24. So, Kevin is 24.

4 0
3 years ago
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One half of a number p is at least 100
4vir4ik [10]

so then P could be any number greater then or equal to 200,hope this helps,please vote me brainliest


5 0
3 years ago
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Evaluate the expression.
mr Goodwill [35]

Answer:

21

Step-by-step explanation:

We need to follow PEMDAS

15+3*2

We need to multiply first

3*2 = 6

Then we add

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21

5 0
2 years ago
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Which pair of numbers is relatively prime
Anna007 [38]
Without any calculations it's evident it can't be neither B (both numbers are even, so they're divisible by 2) nor C (the numbers end in 0 and 5, so they're divisible by 5).

A.
57=3\cdot19\\&#10;96=2^5\cdot3
Both numbers have a factor of 3, so they're not relatively prime.
That means it must be D. But, let's check it.

143=11\cdot13\\&#10;323=17\cdot19

Indeed, those two numbers are relatively prime.

5 0
3 years ago
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