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3 years ago

Find the equation for a parabola with its focus at (0, 3) and a directrix of y = -3.

Mathematics

1 answer:

GrogVix [38]3 years ago

4 0

Answer:

y = (1/12)x^2

Step-by-step explanation:

The vertex of this parabola is halfway between (0, 3) and the directrix, y = -3; that is, it's at (0, 0).

The applicable equation for this vertical parabola is 4py = x^2, where p is the distance between the vertex and the focus. Here that distance is p = 3.

Thus, 4py = x^2 becomes 4(3)y = x^2, or 12y = x^2, or y = (1/12)x^2.

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3 years ago

How much is 12.16% in millions???

horsena [70]

Answer:

12160000.

Step-by-step explanation:

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2 years ago

The basketball coach at a small local college believes that his team plays better and scores more points in front of larger crow

Orlov [11]

Answer:

Step-by-step explanation:

Given that points scored is the dependent variable Y and Number of people attending the game is the independent variable is independent variable x

The correlation coefficient, slope and intercept are calculated as shown below:

x y

378 54

350 57

320 59

478 80

451 82

250 75

489 73

451 53

410 67

215 78

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250 56

450 85

489 101

472 99

Mean 371.0666667 72.4

std dev 117.5138087 15.42632259

covariance 667.5733333

r 0.394558035

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3 years ago

A flat rectangular piece of aluminum has a perimeter of 62 inches. The length is 15

Salsk061 [2.6K]

Answer:

So, the required width of rectangular piece of aluminium is 8 inches

Step-by-step explanation:

We are given:

Perimeter of rectangular piece of aluminium = 62 inches

Let width of rectangular piece of aluminium = w

and length of rectangular piece of aluminium = w+15

We need to find width i.e value of x

The formula for finding perimeter of rectangle is: $Perimeter=2(Length+Width)\\$

Now, Putting values in formula for finding Width w:

$Perimeter=2(Length+Width)\\\\62=2(w+15+w)\\62=2(2w+15)\\62=4w+30\\62-30=4w\\4w=32\\w=\frac{32}{4}\\w=8$

After solving we get the width of rectangular piece :w = 8

So, the required width of rectangular piece of aluminium is 8 inches

6 0

3 years ago