Answer:
As consequence of the Taylor theorem with integral remainder we have that
If we ask that 
has continuous 
th derivative we can apply the mean value theorem for integrals. Then, there exists 
between 
and 
such that
Hence,
Thus,
and the Taylor theorem with Lagrange remainder is
.
Step-by-step explanation:
Answer:
I believe that it might be 24.4
Answer:
90π yd²
Step-by-step explanation:
the surface area of a cylinder is the sum of the lateral area and twice the aera of one end of the cylinder: π·d·l, where l represents the length of the cylinder. Here, the lateral surface area is π·6 yd·12 yd, or 72π yd².
The two ends add the following to the total surface area:
2·π·(d/2)², or 2π·d²/4.
Thus, the total surface area of the cyl. is
A = 2π·(6 yd)²/4 + 72π yd², or
A = 18π yd² + 72π yd² = 90π yd²
Note: Please check your source. L x W + 2pi ·r ^2 is incorrect.
He is, since each number is 4 more in value than the previous number
If you tell me the question I'd be happy to answer. c:
