All categories

2 years ago

Ayo. Bestie. Had enough yet?

Mathematics

1 answer:

choli [55]2 years ago

5 0

Answer:

the answer is e

Step-by-step explanation:

You might be interested in

Find the area of the polygon.

professor190 [17]

The formula for the area of the triangles is base x hight divided by 2 (bh/2)
The formula for the square is length times width (l x w)

therefore...

bh/2 = (12)(6) / 2 = 36 (this is the area of one triangle)

then you need to times 36 by 4 because you have 4 triangles.
36 x 4 = 144

l x w = 12 x 12 = 144 (this is the area of the square)

last you need to add the area of the triangles (144) and the area of the square (144) because that will give you the total surface area of the shape.

144+144= 288

so your answer is 288cm squared (288cm2)

6 0

3 years ago

Read 2 more answers

Answerrr? Please I need help

nadezda [96]

Answer:

Step-by-step explanation:

$f^{3}$ + 11g - 4h

f = 3, g = 2 and h = 7.

Substitute the above values into the expression.

$3^{3}$ + 11 × 2 - 4 × 7

Since there's no addition, subtraction or division signs between 11g and 4h, this basically shows that it is multiplied. Simplify further...

$3^{3}$ is 3×3×3 which equals to 27

11 × 2 equals to 22, and

-4 × 7 = -28

Put all these found values into an expression.

27 + 22 - 28

Use the B.O.D.M.A.S. rule. First we have to add then subtract.

(27 + 22) - 28

49 - 28 = 21

3 0

2 years ago

Read 2 more answers

A certain car depreciates such that its value at the end of each year is p % less than its value at the end of the previous year

icang [17]

Answer:

b(b/a)^2

Step-by-step explanation:

Given that the value of the car depreciates such that its value at the end of each year is p % less than its value at the end of the previous year and that car was worth a dollars on December 31, 2010 and was worth b dollars on December 31, 2011, then

b = a - (p% × a) = a(1-p%)

b/a = 1 - p%

p% = 1 - b/a = (a-b)/a

Let the worth of the car on December 31, 2012 be c

then

c = b - (b × p%) = b(1-p%)

Let the worth of the car on December 31, 2013 be d

then

d = c - (c × p%)

d = c(1-p%)

d = b(1-p%)(1-p%)

d = b(1-p%)^2

d = b(1- (a-b)/a)^2

d = b((a-a+b)/a)^2

d = b(b/a)^2 = b^3/a^2

The car's worth on December 31, 2013 = b(b/a)^2 = b^3/a^2

4 0

3 years ago

Sarah polled 40 randomly selected students at her high school and found that 20% ( = 0.2) are happy with the quality of the cafe

Anna71 [15]

Given:
n = 40, sample size
Confidence level = 99% => z* = 2.58
$\hat{p} = 20\%=0.2$ , sample proportion.

By definition, the margin of error is
$z^{*} \sqrt{ \frac{\hat{p}(1-\hat{p})}{n} } = 2.58 \sqrt{ \frac{(0.2)(0.8)}{40} }= 0.1632$

Answer:
According to Sarah's poll, she can conclude with 99% confidence level that 20% of the high school population is happy with the quality of the cafeteria food, with a margin of error of +/- 16.3%.

5 0

3 years ago

Read 2 more answers

Suppose the newspaper states that the probability of rain today is 60%. what is the probability of the compliment

alexgriva [62]

Complement of "rain today" is "no rain today" and the reuired probability is = 0.7 HOPE I HELPED!!!

5 0

3 years ago