Answer:
V = (About) 22.2, Graph = First graph/Graph in the attachment
Step-by-step explanation:
Remember that in all these cases, we have a specified method to use, the washer method, disk method, and the cylindrical shell method. Keep in mind that the washer and disk method are one in the same, but I feel that the disk method is better as it avoids splitting the integral into two, and rewriting the curves. Here we will go with the disk method.
![\mathrm{V\:=\:\pi \int _a^b\left(r\right)^2dy\:},\\\mathrm{V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy}](https://tex.z-dn.net/?f=%5Cmathrm%7BV%5C%3A%3D%5C%3A%5Cpi%20%5Cint%20_a%5Eb%5Cleft%28r%5Cright%29%5E2dy%5C%3A%7D%2C%5C%5C%5Cmathrm%7BV%5C%3A%3D%5C%3A%5Cint%20_1%5E3%5C%3A%5Cpi%20%5Cleft%5B%5Cleft%281%2B%5Cfrac%7B2%7D%7By%7D%5Cright%29%5E2-1%5Cright%5Ddy%7D)
The plus 1 in '1 + 2/x' is shifting this graph up from where it is rotating, but the negative 1 is subtracting the area between the y-axis and the shaded region, so that when it's flipped around, it becomes a washer.
![V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy,\\\\\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx\\=\pi \cdot \int _1^3\left(1+\frac{2}{y}\right)^2-1dy\\\\\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\= \pi \left(\int _1^3\left(1+\frac{2}{y}\right)^2dy-\int _1^31dy\right)\\\\](https://tex.z-dn.net/?f=V%5C%3A%3D%5C%3A%5Cint%20_1%5E3%5C%3A%5Cpi%20%5Cleft%5B%5Cleft%281%2B%5Cfrac%7B2%7D%7By%7D%5Cright%29%5E2-1%5Cright%5Ddy%2C%5C%5C%5C%5C%5Cmathrm%7BTake%5C%3Athe%5C%3Aconstant%5C%3Aout%7D%3A%5Cquad%20%5Cint%20a%5Ccdot%20f%5Cleft%28x%5Cright%29dx%3Da%5Ccdot%20%5Cint%20f%5Cleft%28x%5Cright%29dx%5C%5C%3D%5Cpi%20%5Ccdot%20%5Cint%20_1%5E3%5Cleft%281%2B%5Cfrac%7B2%7D%7By%7D%5Cright%29%5E2-1dy%5C%5C%5C%5C%5Cmathrm%7BApply%5C%3Athe%5C%3ASum%5C%3ARule%7D%3A%5Cquad%20%5Cint%20f%5Cleft%28x%5Cright%29%5Cpm%20g%5Cleft%28x%5Cright%29dx%3D%5Cint%20f%5Cleft%28x%5Cright%29dx%5Cpm%20%5Cint%20g%5Cleft%28x%5Cright%29dx%5C%5C%3D%20%5Cpi%20%5Cleft%28%5Cint%20_1%5E3%5Cleft%281%2B%5Cfrac%7B2%7D%7By%7D%5Cright%29%5E2dy-%5Cint%20_1%5E31dy%5Cright%29%5C%5C%5C%5C)
Our exact solution will be V = π(4In(3) + 8/3). In decimal form it will be about 22.2 however. Try both solution if you like, but it would be better to use 22.2. Your graph will just be a plot under the curve y = 2/x, the first graph.
First, convert all measurements to inches.
Box 1:
3ft(12in)=36in+6in=42in
Box 2:
4ft(12in)=48in+10in=58in
Box 3:
4ft(12in)=48in+5in=53in
Now, add the heights together.
42in+58in+53in=153in
Finally, convert added height to feet.
153in/12in=12 with a remainder of 9, so your final answer is 12ft 9in
Answer:
1. To eliminate x-term, multiply the second by -2
2. To eliminate y-term, multiply the second by 3
Step-by-step explanation:
4x - 9y = 7 (1)
-2x + 3y = 4 (2)
1. To eliminate x-term, multiply the second by -2
-2x + 3y = 4 (2) × 2
-4x + 6y = 8 (3)
4x - 9y = 7 (1)
Add (3) and (1)
6y - 9y = 8 + 7
-3y = 15
y = 15/-3
y = -5
4x - 9y = 7 (1)
4x - 9(-5) = 7
4x + 45 = 7
4x = 7 - 45
4x = -38
x = -38/4
x = -9.5
4x - 9y = 7 (1)
-2x + 3y = 4 (2)
2. To eliminate y-term, multiply the second by 3
-2x + 3y = 4 (2) × 3
-6x + 9y = 12 (3)
4x - 9y = 7 (1)
-6x + 4x = 12 + 7
-2x = 19
x = 19/-2
x = -9.5
4x - 9y = 7 (1)
4(-9.5) - 9y = 7
-38 - 9y = 7
-38 - 7 = 9y
-45 = 9y
y = -45/9
y = -5
A = LW
A = 320
L = 5W
320 = W(5W)
320 = 5W^2
320/5 = W^2
64 = W^2
sqrt 64 = W
8 = W
L = 5W
L = 5(8)
L = 40
so the length (L) = 40 cm and the width (W) = 8 cm
P = 2(L + W)
P = 2(40 + 8)
P = 2(48)
P = 96 <=====
Answer:in decimal form it is 0.12. in 12/100
Step-by-step explanation:
