All categories

3 years ago

If sin y = cos ( y + 2° )

Mathematics

1 answer:

Oksana_A [137]3 years ago

5 0

Answer:

sdgsdaahdafhfdgdfbxcxcbcvbfdgfdhrtyreqyutrujwrretgafdhgssdfgsdafd

Step-by-step explanation:

You might be interested in

I'm not quite sure how to do this

Sunny_sXe [5.5K]

0.5t+12=t+10.50------set the equations equal to eachother, with t being the number of toppings
1.5=0.5t----subtract 0.5t from each side and 10.5
t=3---if there are 3 toppings the prices will be the same

7 0

3 years ago

How do you do 5x10+11? Please I am d u m b

jasenka [17]

5 x 10 is 50 then 50 + 11 is 61 so I think it would be 61 ;)

4 0

2 years ago

Read 2 more answers

Solve the inequality. 2(4+2x)>5x+5 oxs-2 O X2-2 xs3 x23

mafiozo [28]

For this case we must resolve the following inequality:

$2 (4 + 2x)> 5x + 5$

Applying distributive property on the left side of inequality we have:

$8 + 4x> 5x + 5$

Subtracting 5 from both sides of the inequality:

$8-5 + 4x> 5x\\3 + 4x> 5x$

Subtracting 4x from both sides of the inequality:

$3> 5x-4x\\3> x$

Thus, the result is $x$

Answer:

$x$

5 0

3 years ago

What is the solution to this inequality -13x> - 39

s344n2d4d5 [400]

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

Inequality Form: x < 3

Interval Notation:

( − ∞ , 3 )

3 0

3 years ago

Read 2 more answers

Which expression is equivalent to *picture attached*

Sedbober [7]

Answer:

$\sum_{n=3}^{20}(n(n+1))=\sum _{n=3}^{20} n^2+ \sum _{n=3}^{20} n$

Step-by-step explanation:

Given expression : $\sum_{n=3}^{20}(n(n+1))$

Solving further :

$\Rightarrow \sum_{n=3}^{20}(n^2+n)$

$\Rightarrow \sum _{n=3}^{20} n^2+ \sum _{n=3}^{20} n$

So, $\sum_{n=3}^{20}(n(n+1))=\sum _{n=3}^{20} n^2+ \sum _{n=3}^{20} n$

So, The given expression is equivalent to Option A

So, Option A is the answer

7 0

3 years ago