If sin y = cos ( y + 2° )

Mathematics

1 answer:

Oksana_A [137]3 years ago

5 0

Answer:

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Step-by-step explanation:

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Dayson is covering a package in the shape of a rectangular prism with wrapping paper. The package is 50 centimeters by 20 centim

goblinko [34]

Dayson has 1 m2 of wrapping paper, which is 10000 cm2:
1 m = 100 cm
1 m^2 = (100 cm)^2
1 m^2 = 10000 cm^2
The package has a surface area of cm2:
A = 2*(50*20) + 2*(50*18) + 2*(18*20)
A = 4520 cm^2
The area of the package is less than the area of the wrapping paper (4520 cm^2 < 10000 cm^2). So, Dayson cover the package with the wrapping paper.

3 0

3 years ago

The average amount of water in randomly selected 16-ounce bottles of water is 16.15 ounces with a standard deviation of 0.45 oun

vekshin1

Answer:

0.0179 = 1.79% probability that the mean of this sample is less than 15.99 ounces of water.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .