Greatest common factor in this case is 2s^2. The resulting polynomial would be 2s^2(s^2-2)
Answer:
The solution of |3x-9|≤15 is [-2;8] and the solution |2x-3|≥5 of is (-∞,2] ∪ [8,∞)
Step-by-step explanation:
When solving absolute value inequalities, there are two cases to consider.
Case 1: The expression within the absolute value symbols is positive.
Case 2: The expression within the absolute value symbols is negative.
The solution is the intersection of the solutions of these two cases.
In other words, for any real numbers a and b,
- if |a|> b then a>b or a<-b
- if |a|< b then a<b or a>-b
So, being |3x-9|≤15
Solving: 3x-9 ≤ 15
3x ≤15 + 9
3x ≤24
x ≤24÷3
x≤8
or 3x-9 ≥ -15
3x ≥-15 +9
3x ≥-6
x ≥ (-6)÷3
x ≥ -2
The solution is made up of all the intervals that make the inequality true. Expressing the solution as an interval: [-2;8]
So, being |2x-3|≥5
Solving: 2x-3 ≥ 5
2x ≥ 5 + 3
2x ≥8
x ≥8÷2
x≥8
or 2x-3 ≤ -5
2x ≤-5 +3
2x ≤-2
x ≤ (-2)÷2
x ≤ -2
Expressing the solution as an interval: (-∞,2] ∪ [8,∞)
To factor x²-2x-4, you are looking to answer three questions.
1) What pair of numbers multiplies to 4?
2) What pair of numbers multiplies to 1?
3) Do these pairs when multiplied together, add/subtract to the middle term?
To answer (1), our pairs are 2 and 2, 4 and 1. Since there's a negative with 4 at the end (from question one), the signs will be opposite.
To answer (2), only pair multiplies to 1 - 1 and 1. Let's try both pairs from 1.
(x-4)(x+1) The middle term here is -3x. Nope.
(x-1)(x+4). The middle term here is 3x. Nope.
(x-2)(x+2) The middle term is 0x (or no middle term). Nope.
So x²-2x-4 does not factor.
The domain of the function is 80 to 180 because domain refers to the valid inputs of the function.
After receiving $42, the new domain (<em>that Albert can afford)</em> is from 80 to 147.
All you need to do is pull out the common factor of
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