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GaryK [48]
3 years ago
9

Stewart soaps began business by issuing 25,000 shares of $5 par value common stock for $20 per share. during its first year, the

corporation sustained a net loss of $5,000. the year-end balance sheet would show
Business
1 answer:
larisa [96]3 years ago
6 0
Issuing 25,000 shares of $5 par value common stock for $20 per share.

Cash (25,000 x 20)                           500,000
         Common stock (25,000 x 5)                          125,000
         Additional Paid-In Capital (25,000 x 15)           375,000
 
The net loss will only be reflected as a deduction from retained earnings. Retained earnings is where the net income or net loss of the company will be under in the year-end balance sheet. It is the balance of all income and loss the company has since its inception. 
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When the relationship between government and interest groups becomes entangled and tight with some groups having formal governme
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A production facility employs 10 workers on the day shift, 8 workers on the swing shift, and 6 workers on the graveyard shift. A
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Answer:

The answer is below

Explanation:

A What is the probability that all 4 selected workers will be the day shift?

B What is the probability that all 4 selected workers will be the same shift?

C What is the probability that at least two different shifts will be represented among the selected workers.

A)

The total number of workers = 10 + 8 + 6 = 24

The probability that all 4 selected workers will be the day shift is given as:

P_a=\frac{C(10,4)}{C(24,4)}= \frac{210}{10626}=0.0198

C(n,r)=\frac{n!}{(n-r)!r!}

B) The probability that all 4 selected workers will be the same shift (P_B) = probability that all 4 selected workers will be the day shift + probability that all 4 selected workers will be the swing shift + probability that all 4 selected workers will be the graveyard shift.

Hence:

P_B=\frac{C(10,4)}{C(24,4)}+\frac{C(8,4)}{C(24,4)}+\frac{C(6,4)}{C(24,4)}=0.0198+0.0066+0.0014=0.0278

C) The probability that at least two different shifts will be represented among the selected workers (P_C)= 1 - the probability that all 4 selected workers will be the same shift(P_B)

P_C=1-P_B\\\\P_C=1-0.0278\\\\P_C=0.972

7 0
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