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2 years ago

Very much appreciated if someone can kindly help haha

Mathematics

1 answer:

Artemon [7]2 years ago

7 0

I cant see the pic sorry

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Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar. Find the remainder

victus00 [196]

Answer:

Step-by-step explanation:

Given:

(h⁴ + h² – 2) ÷ (h + 3).

We could obtain the remainder using the remainder theorem :

That is the remainder obtained when (h⁴ + h² – 2) is divided by (h + 3).

Using the reminder theorem,

Equate h+3 to 0 and obtain the value of h at h+3 = 0

h + 3 = 0 ; h = - 3

Substituting h = - 3 into (h⁴ + h² – 2) to obtain the remainder

h⁴ + h² – 2 = (-3)⁴ + (-3)² - 2 = 81 + 9 - 2 = 88

Hence, remainder is 88

4 0

2 years ago

Whats -5/3+ 2 1/3 please help i dont wanna failPLWASEEE

Softa [21]

Step-by-step explanation:

$= - \frac{5}{3} + 2 \frac{1}{3}$

$= - \frac{5}{3} + \frac{7}{3}$

$= \frac{2}{3}$

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2 years ago

Calculate the length of AD using Pythagoras theorem, leave your answer in surd form

erma4kov [3.2K]

Broyouraidiotbroooooo

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2 years ago

Find the sum of the measures of the exterior angles of a convex 21-gon

rusak2 [61]

4140

21-2(180)=3420 3420/21=162.8571 etc. 360-162.9=197.1 197.1 times 21 is (4140)

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2 years ago

Astronomers treat the number of stars X in a given volume of space as Poisson random variable. The density of stars in the Milky

cupoosta [38]

Answer:

Explained below.

Step-by-step explanation:

The random variable X is defined as the number of stars in a given volume of space.

$X\sim \text{Poisson}\ (\lambda=1)$

The probability mass function of X is:

$p_{X}(x)=\frac{e^{-\lambda}\lambda^{x}}{x!}$

(7)

Compute the probability of exactly two stars in 16 cubic light-years as follows:

$P(X=2)=\frac{e^{-1}\times 1^{2}}{2!}=\frac{e^{-1}}{2}=\frac{0.36788}{2}=0.18394\approx 0.184$

(8)

Compute the probability of three or more stars in 16 cubic light-years as follows:

$P(X\geq 3)=1-P(X$

(9)

In 16 cubic light years there is only 1 star.

Then in 1 cubic light years there will be, (1/16) stars.

Then in 4 cubic light years there will be, 4 × (1/16) = (1/4) stars.

(10)

In 16 cubic light years there is only 1 star.

Then in 1 cubic light years there will be, (1/16) stars.

Then in t cubic light years there will be, [t × (1/16)] stars.

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2 years ago