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PilotLPTM [1.2K]
4 years ago
8

What is the median of the data 17,18,19,20,21,22,23.1

Mathematics
2 answers:
zimovet [89]4 years ago
5 0
The median is twnety
NeX [460]4 years ago
4 0
The answer to this is 20
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Brandon is playing hide-and-seek with Katy and Tony. Katy is hiding 63 feet south of Brandon, and Tony is hiding due east of Kat
sergij07 [2.7K]

Answer:

60 feets

Step-by-step explanation:

Given that :

Using Pythagoras rule :

Hypotenus = sqrt(Adjacent^2 + opposite^2)

From the attached picture :

x² = 87^2 - 63^2

x^2 = 7569 - 3969

X^2 = 3600

Take the square root of both sides :

X = sqrt(3600)

X = 60 feets

Hence, Katy and Tony are 60 feets apart

6 0
3 years ago
If $3,500 is invested at a rate of 6% , compounded continuously, approximately what amount of time would be needed to have a bal
Akimi4 [234]
D.0.21 years is the answer
4 0
3 years ago
The Miguel traces a circle with the radius of 25 cm like the one shown. He will color the shade section what is the area of the
Scilla [17]

Answer: The area of shaded section is 491.07 cm²

Step-by-step explanation:

Given: Radius of the circle = 25 cm

Now as shown in figure the shaded region is a quadrant.

Therefore the central angle is 90°

Now as we know

Area of sector is given by

Area= \pi r^2 \dfrac{\theta}{360^\circ}  where r is radius and \theta is central angle

So we have

Area = \dfrac{22}{7} \times (25)^2\times \dfrac{90^\circ}{360^\circ} \\\\\Rightarrow Area=  \dfrac{22}{7} \times 625 \times \dfrac{1}{4} \\\\\Rightarrow Area=  \dfrac{11}{7} \times 625 \times \dfrac{1}{2} = 491.07cm^2

Hence, the area of shaded section is 491.07 cm²

5 0
3 years ago
(10.5-7)+(4x3) help please
Leno4ka [110]

Answer: 15.5

Step-by-step explanation:

(10.5-7)+(4x3)

following PEDAS we do operations in parentheses first

10.5-7=3.5

4x3=12

we now have 3.5+12 as our intermediate expression

and 3.5+12 = 15.5

8 0
3 years ago
Read 2 more answers
Select the correct answer.
Crazy boy [7]

check the picture below.

now, if we split that triangle like so with that red line, we can use the right-triangle there, to get θ.


\bf tan(\theta )=\cfrac{\stackrel{opposite}{3}}{\stackrel{adjacent}{3}}\implies tan(\theta )=1\implies tan^{-1}(\theta )=tan^{-1}(1)\implies \measuredangle \theta =\cfrac{\pi }{4}

8 0
3 years ago
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