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Naddika [18.5K]

3 years ago

10

A recipe calls for 2 1/5 cups of chopped tomatoes and 3 2/5 cups of diced turnips how many more cups of turnips did the recipe c

alled for

2 answers:

Zarrin [17]3 years ago

6 0

The answer would be 1 1/5 more turnips.

iren [92.7K]3 years ago

5 0

2/5 is how much more turnips he is using

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Natalia paid $38.95 for three medium-sized pizzas and a salad. Solve an equation to find the cost of one pizza,p, if Natalia pai

Vedmedyk [2.9K]

One Pizza is 8.99 hope this helps

7 0

3 years ago

Read 2 more answers

You have 23 1/2 pounds of blueberries to store in freezer bags. Each bag holds 3 3/4 pounds of blueberries. What is the minimum

monitta

Answer:

The minimum number of freezer bags needed to store all the blueberries is 7

Step-by-step explanation:

we know that

To find out the number of freezer bags needed , divide the total pounds of blueberries by 3 3/4, but first convert mixed number to an improper fraction

$23\frac{1}{2}\ lb=\frac{23*2+1}{2}=\frac{47}{2}\ lb$

$3\frac{3}{4}\ lb=\frac{3*4+3}{4}=\frac{15}{4}\ lb$

$\frac{47}{2}:\frac{15}{4}=\frac{47*4}{2*15} =\frac{94}{15}=6.3\ bags$

Round up

7 bags

therefore

The minimum number of freezer bags needed to store all the blueberries is 7

7 0

3 years ago

What is -2 = 5 / (2x+3)

LUCKY_DIMON [66]

Answer:

x = -11/4

Step-by-step explanation:

Given that:

-2 = 5 / (2x+3)

Multiplying both sides by (2x + 3)

-2(2x + 3) = 5

"-" sign will alter the inner signs

-4x -6 = 5

Adding 6 on both sides:

-4x -6 +6 = 5 + 6

-4x = 11

Dividing both sides by -4

-4x/-4 = 11/-4

x = -11/4

i hope it will help you!

3 0

3 years ago

How do you divide 6114 by 63

viva [34]

You put it in a calculator and you get 97.06349206.

8 0

3 years ago

Calculate A^2, given A=[tex]Given A=[−3 4/-2 0}

MatroZZZ [7]

Answer:

$\large\boxed{A^2=\left[\begin{array}{ccc}1&-12\\6&-8\end{array}\right] }$

Step-by-step explanation:

$A=\left[\begin{array}{ccc}-3&4\\-2&0\end{array}\right]\\\\A^2=\left[\begin{array}{ccc}-3&4\\-2&0\end{array}\right] \cdot\left[\begin{array}{ccc}-3&4\\-2&0\end{array}\right] =\left[\begin{array}{ccc}(-3)(-3)+(4)(-2)&(-3)(4)+(4)(0)\\(-2)(-3)+(0)(-2)&(-2)(4)+(0)(0)\end{array}\right]\\\\A^2=\left[\begin{array}{ccc}1&-12\\6&-8\end{array}\right]$

8 0

3 years ago