Answer:
H = 5 , W = 8 , L = 16
Step-by-step explanation:
Use the distance formula
And just plug in your numbers and solve
Answer:
-8/15
Step-by-step explanation:
So remember what sin, cos, and tan are.
sin = opposite/hypotenuse
cos = adjacent/hypotenuse
tan = opposite/adjacent
Now, using what we know of sin and cos, lets find opposite and adjacent to solve for tan.
Sin=-8/17
So this must mean that opposite is -8, and the hypotenuse is 17.
Next, lets find adjacent. Cos = 15/17
So this must mean that adjacent is 15, and again, hypotenuse is 17.
Now lets take the -8 of the opposite, and 15 of the adjacent, and get tan.
<u>Tan: -8/15. </u>
17 is not included in this whatsoever, since hypotenuse is not included in tan. And remember that it cannot be -15/8, since its opposite/adjacent, not adjacent/opposite.
Hope this helps!
Around 5.9 since if u divide 5.2 by 7 it would .74 just multiply that by 7 and round ur answers.
Answer:
I'm gonna rewrite each sentence in a way that lines up a little more with the Algebraic expression you would end up with. Just keep in mind that either way of saying it is correct.
1. "8 times some number (a variable) minus 5"
8x-5
2. "13 plus some number"
13+x
3. "Some number over 7"
x/7 or x÷7
4. "d number of drinks times 3.50 plus 12 equals how much John spent (we'll call it J)"
12+3.50d = J
5. "Stacey bowled x number of games times the cost of one game (call it B) plus the cost of the shoes (call it P) which equals how much they spent (call it S)"
xB+P = S
6. "675.95 dollars was spent at the mall by a number of players (call it P) to equal the total cost per player)"
$675.95÷p (players) = 675.95/p (dollars/player)
Essentially you're making expressions or equations out of numbers you know and putting in variables as place holders for numbers you don't know. The variables can be whatever letters you like, but you'll want to write what each variable represents down nearby. Otherwise the reader/your teacher won't know what's what.
