3(х + 3) 3х + 3 please help

Prove that the gregorian calendar repeats itself every 400 years.

Setler79 [48]

The calendar obviously has an integral number of years and months in 400 years. If it has an integral number of weeks, then it will repeat itself after that time. The rules of the calendar eliminate a leap year in 3 out of the four century years, so there are 97 leap years in 400 years. The number of excess days of the week in 400 years can be found by ...

(303·365) mod 7 + (97·366) mod 7 = (2·1 + 6·2) mod 7 = 14 mod 7 = 0

Thus, there are also an integral number of weeks in 400 years.

The first day of the week is the same at the start of every 400-year interval, so the calendar repeats every 400 years.

3 0

3 years ago

It is hard to calculate the volume of a mountain but several estimates put the volume of Mount Everest at around 2,413 cubic kil

scoray [572]

Answer:

About 609,000 Cowboy stadiums could fit inside of Mount Everest

Step-by-step explanation:

we have

The estimate volume of Mount Everest is at around $2,413\ km^{3}$

The Dallas Cowboys Stadium has a volume of $140,000,000\ ft^{3}$

step 1

Convert ft³ to km³

we know that

1 km=3,280.84 ft

so

$140,000,000\ ft^{3}=140,000,000*(1/3,280.84)^{3}=0.003964\ km^{3}$

step 2

To find how many Cowboy stadiums could fit inside of Mount Everest, divide the volume of Mount Everest by the volume of the Dallas Cowboys Stadium

$2,413/0.003964=608,729$

Round to the nearest Thousands

$608,729=609,000$

The volume of Mount Everest is about 609,000 times greater than the volume of the Dallas Cowboys Stadium

8 0

2 years ago

During gym class, Alexis played dodgeball for 34 hour.

IRISSAK [1]

the soultion in 20

Step-by-step explanation:

first get the 34 hour of dogeball and get the 14 hour of basketball subtract 34 - 14 first 4 - 4 = 0 then 30 - 10 = 20

6 0

2 years ago

Read 2 more answers

I really need help with this equation

zimovet [89]

M = -6.5, because -6.5 times itself -5 times, it will be equivalent to 1/32.
I hope I helped! :-)

6 0

2 years ago

Read 2 more answers

The equation of a circle is given below.

BARSIC [14]

Given:

The equation of the circle is $x^2+(y+4)^2=64$

We need to determine the center and radius of the circle.

Center:

The general form of the equation of the circle is $(x-h)^2+(y-k)^2=r^2$

where (h,k) is the center of the circle and r is the radius.

Let us compare the general form of the equation of the circle with the given equation $x^2+(y+4)^2=64$ to determine the center.

The given equation can be written as,

$(x-0)^2+(y+4)^2=64$

Comparing the two equations, we get;

(h,k) = (0,-4)

Therefore, the center of the circle is (0,-4)

Radius:

Let us compare the general form of the equation of the circle with the given equation $x^2+(y+4)^2=64$ to determine the radius.

Hence, the given equation can be written as,

$x^2+(y+4)^2=8^2$

Comparing the two equation, we get;

$r^2=8^2$

$r=8$

Thus, the radius of the circle is 8

3 0

3 years ago

3(х + 3) 3х + 3 please help​

3(х + 3) 3х + 3 please help