All categories

3 years ago

Find the distance from E to F

Mathematics

1 answer:

ludmilkaskok [199]3 years ago

7 0

Answer/Step-by-step explanation:

To find the distance of E to F, subtract the distance of DE from the total.

28 - 11 = 17

EF = 17

You might be interested in

Solve the equation log^7b>2

ahrayia [7]

Answer:

b > 12.71

Step-by-step explanation:

Here in this question we have to solve the inequality equation given for b (An unknown variable}

Now, the equation is $(\log b)^{7} > 2$

⇒ $\log b > 2^{\frac{1}{7} }$

We are taking the base of the log here is 10.

So, $10^{(\log b)} > 10^{2^{\frac{1}{7} } }$ {Since $10^{\log x} =x$ and $e^{\ln x} = x$ }

⇒ b > 12.71 (Approximate) (Answer)

3 0

3 years ago

If you earn $3500 per month and you expect your earnings to increase by 2.3% per year, how much do you think you will be making

Y_Kistochka [10]

$\bf \qquad \textit{Amount for Exponential Growth}\\\\
A=I(1 + r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
I=\textit{initial amount}\to &3500\\
r=rate\to 2.3\%\to \frac{2.3}{100}\to &0.023\\
t=\textit{elapsed time}\to &10\\
\end{cases}
\\\\\\
A=3500(1+0.023)^{10}$

8 0

4 years ago

a landscaping company needs 160 gallons of 40% fertilize the shrubs in an office park. They have in stock 50% fertilizer and 30%

Novay_Z [31]

Let

x--------> volume of 50% fertilizer

y--------> volume of 30% fertilizer

we know that

x+y=160-----> x=160-y-----> equation 1

x*0.5+y*0.3=160*0.4-----> equation 2

substitute equation 1 in equation 2

[160-y]*0.5+0.3*y=63.8----> 77-0.35*y+0.25*y=63.8

0.10*y=13.2------> y=13.2/0.10----> y=132 gal

x=220-y----> x=220-132----> x=88 gal

the answer is

88 gal of 50% fertilizer

132 gal 30% fertilizer

5 0

3 years ago

Select the four points that appear on the line with the given slope and y-intercept

zysi [14]

I’m pretty sure the Points are B, D, E and F

5 0

3 years ago

What is 4th cube number

IrinaK [193]

Answer:

31, 27

Step-by-step explanation:

6 0

3 years ago