Question

Which equation shows a valid, practical step in solving?

Answer 1

Answer:

D) $(\sqrt[4]{2x -8} )^4 = (-\sqrt[4]{2x + 8} )^4$

Step-by-step explanation:

The given equation is $\sqrt[4]{2x - 8} + \sqrt[4]{2x + 8 } = 0$

Before, solve this equation, we have to get rid off the radical sign.

So we move the second term on the other side.

$\sqrt[4]{2x-8} = -\sqrt[4]{2x + 8}$

Since we have to radical of 4, we need to raise the power to 4 on both sides

$(\sqrt[4]{2x - 8)} )^4 = (-\sqrt[4]{2x + 8} )^4$

Thank you.