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Murljashka [212]
4 years ago
11

Which equation shows a valid, practical step in solving?

Mathematics
1 answer:
Slav-nsk [51]4 years ago
7 0

Answer:

D) (\sqrt[4]{2x -8} )^4 = (-\sqrt[4]{2x + 8} )^4

Step-by-step explanation:

The given equation is \sqrt[4]{2x - 8}  + \sqrt[4]{2x + 8 } = 0

Before, solve this equation, we have to get rid off the radical sign.

So we move the second term on the other side.

\sqrt[4]{2x-8} = -\sqrt[4]{2x + 8}

Since we have to radical of 4, we need to raise the power to 4 on both sides

(\sqrt[4]{2x - 8)} )^4 = (-\sqrt[4]{2x + 8} )^4\\

Thank you.

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