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alisha [4.7K]
3 years ago
7

One equation in a system of equations is y = 3/4x - 1. For which second equation would the system have exactly one solution? cho

ose ALL that apply.
A. y = 3/4x - 1/4

B. y = 6x + 5

C. y = 4/3x - 8/3

D. y = 3/4x + 1/2

E. y = 2x - 7​
Mathematics
1 answer:
Zina [86]3 years ago
5 0

Answer:

ace

Step-by-step explanation:

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Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
kvasek [131]

Answer:

h=\frac{V}{\pi r^2}

Step-by-step explanation:

To write this equation with h isolated, we cancel everything else on the right hand side of the equals sign.  This means we cancel π and r².

Since both of these are attached to h by multiplication, we divide by both to cancel.  We can divide by both at the same time:

\frac{V}{\pi r^2}=\frac{\pi r^2h}{\pi r^2}\\\\\frac{V}{\pi r^2}=h

7 0
3 years ago
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Which are the correct measures for
-BARSIC- [3]

Answer:

option c is the correct answer

Step-by-step explanation:

∠YXZ+117°=180°

∠YXZ=180°-117°

∠YXZ=63°

63°+36°+∠YZX=180°(sum of angles is 180)

99°+∠YZX=180

∠YZX=180-99

∠YZX=81

5 0
3 years ago
What is the value of x in equation 0.2(x+1)+ 0.5x = - 0.3(x-4)
Greeley [361]

Answer: x=1

Step-by-step explanation:

6 0
3 years ago
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solve this system of linear equations. separate the x- and y- values with a comma. 6x +5y=-19 12x-8y=52
Ymorist [56]

ANSWER

The solution is

(x,y)=(1,-5)

EXPLANATION

The equations are:

1st equation: 6x +5y=-19

2nd equation: 12x-8y=52

Multiply the first equation by 2:

3rd equation: 12x +10y=-38

Subtracy the 2nd equation from the 3rd equations.

12x-12x+10y--8y=-38-52

18y=-90

Divide both sides by 18.

y=-5

Put y=-5 into any of the equations and solve for x.

Preferably, the first equation will do.

6x +5(-5)=-19

6x -25=-19

6x=25-19

6x=6

x=1

The solution is

(x,y)=(1,-5)

8 0
3 years ago
Please answer thank u i give brainliest to best answer
boyakko [2]

Answer:

A, B, C,

Step-by-step explanation:

Just use a calculator...?

a)

2^-^2*2^8=\frac{1}{2^2}*2^8=\frac{2^8}{2^2}=2^8^-^6=2^6=64\\

b)

3^-^5*3^1=\frac{1}{3^5}*3=\frac{3}{243}=\frac{1}{81}

c)

4^4*4^-^3=\frac{4^4}{4^3}=4^1=4

d)

5^3*5^-^1=\frac{5^3}{5^1}=5^2=25

e)

6^-^8*6^-^6=\frac{6^6}{6^8}=6^-^2=\frac{1}{6^2}=\frac{1}{36}

f)

8^2*8^-^4=\frac{8^2}{8^4}=8^-^2=\frac{1}{8^2}=\frac{1}{64}

3 0
3 years ago
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