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Savatey [412]
3 years ago
15

Help&EXPLAIN •••••••••••••••••••

Mathematics
1 answer:
TiliK225 [7]3 years ago
5 0

Answer:

68cm^2

Step-by-step explanation:

Well there's not much to explain - the problem statement does it for us.

The surface area is equal to the sum of areas of the walls. There's 2 l*w walls, 2 l*h walls and 2 h*w walls.

SA = 2*l*h + 2*l*w + 2*h*w

SA = 2*4cm*6cm + 2*4cm*1cm + 2*6cm*1cm = 48cm^2 + 8cm^2 + 12cm^2 = 68cm^2

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Which of the following statements does NOT adequately describe a developmental progression?
Artyom0805 [142]

The statement which does not adequately describe a developmental progression is Choice C- A developmental progression is a skill check- list that four-years- olds must master to be prepared for kindergarten.

<h3>What is developmental progression?</h3>

The Developmental Progression of Functional Skills is a concept which describes the child's growth in which case, the child's develops relationship with family members and a sense of self in the process and this concept in discuss is not limited to four-year olds.

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6 0
1 year ago
Please Help !!!
solong [7]
Best Answer: 2 LiCl = 2 Li + Cl2
mass Li = 56.8 mL x 0.534 g/mL=30.3 g
moles Li = 30.3 g / 6.941 g/mol=4.37
the ratio between Li and LiCl is 2 : 2 ( or 1 : 1)

moles LiCl required = 4.37
mass LiCl = 4.37 mol x 42.394 g/mol=185.3 g


Cu + 2 AgNO3 = Cu/NO3)2 + 2 Ag
the ratio between Cu and AgNO3 is 1 : 2
moles AgNO3 required = 4.2 x 2 = 8.4 : but we have only 6.3 moles of AgNO3 so AgNO3 is the limiting reactant
moles Cu reacted = 6.3 / 2 = 3.15
moles Cu in excess = 4.2 - 3.15 =1.05

N2 + 3 H2 = 2 NH3
moles N2 = 42.5 g / 28.0134 g/mol=1.52
the ratio between N2 and H2 is 1 : 3
moles H2 required = 1.52 x 3 =4.56
actual moles H2 = 10.1 g / 2.016 g/mol= 5.00 so H2 is in excess and N2 is the limiting reactant
moles NH3 = 1.52 x 2 = 3.04
mass NH3 = 3.04 x 17.0337 g/mol=51.8 g
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5 0
4 years ago
19/92 written as a percentage
Solnce55 [7]

Answer:

20.65%

Step-by-step explanation:

\frac{19}{92}   \\  \\ =  \frac{19 \times 100}{92}  \% \\  \\  =   \frac{1900}{92} \% \\  \\  = 20.6521739 \%\\  \\  = 20.65\%

4 0
3 years ago
Which of the following equations is an example of inverse variation between
Romashka [77]

For this case we have that by definition, a direct variation is given by:

y = kx

Where:

k: It is the constant of proportionality of the variables.

On the other hand, we have that the inverse variation is given by:

y = \frac {k} {x}

Where:

k: It is the constant of proportionality of the variables.

In this way, the correct option is: y = \frac {9} {x}

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Option A

3 0
3 years ago
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