Answer:
so the sides would have to be equal for all sides
2x-3=3x-8 -3=x-8 x=5
x-12, 4x-1, neither, or both?
2x-3=x-12 x-3=-12 x=-9
4x-1=3x-8 x-1=-8 x=-7
2x-3=4x-1 -3=2x-1 -4 = 2x x=-2
3x-8=x-12 2x-8=-12 2x=-4 x=-2
So the answer is neither or C
8:15 a.m to 12:45 p.m......4 hrs 30 min
took 45 min lunch (not paid)....now its 1:30 p.m.....
1:30 p.m. to 6:45 pm = 5 hrs 15 min
5 hrs 15 min + 4 hrs 30 min = 9 hrs 45 min or 9 3/4 hrs
$ 16 for first 8 hrs......overtime pay is $ 24 per hr....leaving 1 hr and 45 min or 1 3/4 hrs overtime
16 + 24(7/4) = 16 + 42 = $ 58 <===
EXPLANATION
The nth term of the sequence is given by
![U_n=a+(n-1)d](https://tex.z-dn.net/?f=U_n%3Da%2B%28n-1%29d%20)
Where
is the first term and
is the constant difference.
We were given that,
S we just need the common difference to write the nth term.
We can get that from another information given to us.
We were also given that the 4th term is 6. This gives the equation.
We substitute
to obtain
Or
This implies,
![d=-2-2](https://tex.z-dn.net/?f=d%3D-2-2)
We substitute these values into the general formula to obtain,
![U_n=6+(n-1)\times-4](https://tex.z-dn.net/?f=U_n%3D6%2B%28n-1%29%5Ctimes-4)
This gives us,
![U_n=6+-4n+4](https://tex.z-dn.net/?f=U_n%3D6%2B-4n%2B4)
![U_n=10-4n](https://tex.z-dn.net/?f=U_n%3D10-4n)
Hence the nth term of the sequence is,
![10-4n](https://tex.z-dn.net/?f=10-4n)
Given :
A submarine started at the surface of the water and was moving at -15 meters per minute.
The submarine traveled at this rate for 48 minutes before coming to rest on the ocean floor.
To Find :
The change in the submarine position.
Solution :
We need to find the position of submarine position from the surface of water.
Distance travelled = Speed × Time
Distance travelled = -15 m/min × 48 min
Distance travelled = 720 m
Therefore, the position of submarine is 720 m below the surface of ocean.
Step 1 Given. The problem is telling us to start with the equation 4<span>·0=0
Step 2 Substitute. Any number plus its opposite is zero. Since the opposite of 10 is -10, 10+(-10)= 0: 4(10+-10)=0
Step 3 Use the distributive property. In other words multiply 4 by 10 and 4 by -10: 4</span>·10+4·-10=0
Step 4 Multiply. perform the first multiplication of step 3: 4·10=40, so: 40+4·-10=0
Step 5 Subtract 40 from both sides. 40-40+4·-10=0-40; simplify the left side: 0+4·-10=0-40
4·-10=0-40
Step 5 Simplify to solve for 4·-10. Simplify the right side: 4·-10=-40
We can conclude that you should fill your table as follows:
Step 1 Given. 4·0=0
Step 2 Substitute. Any number plus its opposite is zero. 4(10+-10)=0
Step 3 Use the distributive property. 4·10+4·-10=0
Step 4 Multiply. 40+4·-10=0
Step 5 Subtract 40 from both sides. 4·-10=0-40
Step 5 Simplify to solve for 4·-10. 4·-10=-40