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kow [346]
4 years ago
17

What value represents the vertical translation from the graph of the parent function f(x) = x2 to the graph of the function

Mathematics
2 answers:
djyliett [7]4 years ago
8 0

Answer:

Shifted 3 units upwards.

Step-by-step explanation:

We have been given a parent function f(x)=x^2 and a translated function f(x)=(x+5)^2+3. We are asked to determine the vertical translation from the parent function to f(x)=(x+5)^2+3.

Let us recall translation rules.

Horizontal translation:

f(x)\rightarrow f(x-a)=\text{Graph shifted to right by a units}

f(x)\rightarrow f(x+a)=\text{Graph shifted to left by a units}

Vertical translation:

f(x)\rightarrow f(x)-a=\text{Graph shifted downwards by a units}

f(x)\rightarrow f(x)+a=\text{Graph shifted upwards by a units}

Upon looking at our given function, we can see that the value of 'a' is positive 5 inside parenthesis, so our graph is shifted to left by 5 units.

We can also see that the value of 'a' outside parenthesis is positive 3, therefore, the graph of parent function is shifted upwards by 3 units to get the graph of function f(x)=(x+5)^2+3.

choli [55]4 years ago
4 0
The +3 is the vertical and the +5 tells you horizontal.  so this graph moves 3 up and 5 left. But since it only wants vertical that would be the +3
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y=x^2 +64x + 12\\ \\a=1,\ b=64 \ c = 12 \\ \\h = \frac{-64}{2}=-32 \\ \\ k = 12 -\frac{64^2}{4 }=12-\frac{4096}{4}=12-1024= -1012\\ \\y =  (x+32)^2-1012 \\ \\ This \ means \  the \  vertex \ of \ the \  parabola \ is \ at \ the \  point \ (-32, -1012)\\ \\ and \ the \  parabola \ is \ concave \ up.




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