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elena55 [62]
2 years ago
5

class="latex-formula">
Mathematics
2 answers:
Liula [17]2 years ago
8 0

\green{ \rule{50cm}{0.01cm}}

\red{ \rule{50cm}{0.01cm}}

\green{ \rule{50cm}{0.01cm}}

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The value of x is :

  • - 8

\large \boxed{ \mathfrak{Explanation}}

let's solve ~

  • x - 17 =  - 25

  • x =  - 25 + 17

  • x =  - 8

\green{ \rule{50cm}{0.01cm}}

\red{ \rule{50cm}{0.01cm}}

\green{ \rule{50cm}{0.01cm}}

Sonbull [250]2 years ago
5 0
To solve this, add 17 to both sides:
x = -25 + 17
x = -8
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A painter has a 24 foot ladder that he is using to paint a house. For safety reasons, the ladder must be placed at least 8 feet
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Answer:

The ladder can reach a height of 22.6 feet.  

Step-by-step explanation:

In order to find the height that the ladder can reach, you need to use the Pythagorean Theorem.  The Pythagorean Theorem assumes that the house to the ground will form a right triangle and the leaning ladder is the hypotenuse.  Using the formula:  a² + b² = c², we can plug in the values that we know and solve for the missing variable.  In this case we know the base of the triangle 'b' and the hypotenuse 'c':  a² + 8² = 24² or a² + 64 = 576.  To solve for a, we must first subtract 64 from both sides:  a² + 64 - 64 = 576 - 64 or a² = 512.  In order to find just the value of 'a', which represents the height, we need to take the square root of both sides:  √a² = √512 or a ≈ 22.6 feet.

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3 years ago
A rectangle on a coordinate plane has vertices Q(Negative 1, 1), R(6, 1), S(6, Negative 8), and T(Negative 1, Negative 8). What
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Step-by-step explanation:

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3 0
3 years ago
What is the answer for y^2+17y+170
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5 0
3 years ago
Mark's school is selling tickets to the annual dance competition. On the first day of ticket sales the school sold 4 senior tick
erica [24]

The cost of each senior ticket is $ 5 and cost of each child ticket is $ 12

<em><u>Solution:</u></em>

Let "a" be the price of each senior ticket

Let "b" be the price of each child ticket

<em><u>On the first day of ticket sales the school sold 4 senior tickets and 4 child tickets for a to total of 68</u></em>

Thus a equation is framed as:

4 senior tickets x price of each senior ticket + 4 child tickets x price of each child ticket = 68

4 \times a + 4 \times b = 68

4a + 4b = 68 ---------- eqn 1

<em><u>The school took in 120 on the second day by selling 12 senior tickets and 5 child tickets</u></em>

Similarly, we frame a equation as:

12 \times a + 5 \times b = 120

12a + 5b = 120 ---------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>Multiply eqn 1 by 3</u></em>

12a + 12b = 204 -------- eqn 3

<em><u>Subtract eqn 2 from eqn 3</u></em>

12a + 12b = 204

12a + 5b = 120

( - ) --------------

7b = 84

b = 12

<em><u>Substitute b = 12 in eqn 1</u></em>

4a + 4(12) = 68

4a + 48 = 68

4a = 20

a = 5

Thus cost of each senior ticket is $ 5 and cost of each child ticket is $ 12

4 0
2 years ago
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