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elena55 [62]
2 years ago
5

class="latex-formula">
Mathematics
2 answers:
Liula [17]2 years ago
8 0

\green{ \rule{50cm}{0.01cm}}

\red{ \rule{50cm}{0.01cm}}

\green{ \rule{50cm}{0.01cm}}

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The value of x is :

  • - 8

\large \boxed{ \mathfrak{Explanation}}

let's solve ~

  • x - 17 =  - 25

  • x =  - 25 + 17

  • x =  - 8

\green{ \rule{50cm}{0.01cm}}

\red{ \rule{50cm}{0.01cm}}

\green{ \rule{50cm}{0.01cm}}

Sonbull [250]2 years ago
5 0
To solve this, add 17 to both sides:
x = -25 + 17
x = -8
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Find the least number by which 243 must be divided to make it a perfect<br> square.
yaroslaw [1]

Answer:

Step-by-step explanation:

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  • Step two Is it a perfect square. No 243 just cant be a perfect square.
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4 0
3 years ago
2c+6= 30<br> work out the value of c
Dafna1 [17]

Answer:

2c + 6 = 30

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c = 12

8 0
2 years ago
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Flura [38]

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$30240.96

Step-by-step explanation:

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2 years ago
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Pls help me
masha68 [24]

Answer:

Step-by-step explanation:

Volume of the figure = Base area * height

Base area:

Base area = area of trpezium + area of triangle

<u />

<u>Trapezium:</u>

a, b area the length of parallel sides and h is the height of trapezium.

a = 8 m ; b =  5 m & h = 3 m

\boxed{ \text{ Area of trapezium = $\dfrac{(a +b)*h}{2} $}}

                               =\dfrac{(8+5)*3}{2}\\\\\\=\dfrac{13*3}{2}\\\\\\= \dfrac{39}{2}\\\\\\= 19.5 \ m^{2}

<u>Triangle:</u>

height = 4 m & base = 8 m

\boxed{\text{Area of triangle =$\dfrac{1}{2}*base*height$}}

                           =\dfrac{1}{2}*8*4\\\\\\= 4*4\\\\= 16 \ m^{2}

Base area = 19.5 + 16

                 = 35.5 m²

Volume of the figure = Base area * height

                                     = 35.5 * 14

                                      = 497 m³

8 0
2 years ago
Evaluate 2y+x2÷4 when x=6 and y=4. I got 44 but it said it was wrong please help need an explanation as well
statuscvo [17]

Answer:

17

Step-by-step explanation:

2 (4) + 6^2 / 4 = 8 + 36 / 4 = 8 + 9 = 17.

When solving these types of problems, make sure to use BEDMAS. For example, in this question, do x^2 / 4 before 2y + (x^2 / 4).

7 0
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