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Anettt [7]
3 years ago
10

1.9 mol HCl and 3.9 mol NaOH react according to the equation HCl + NaOH −→ NaCl + H2O . If the limiting reactant is HCl, calcula

te the amount of NaCl formed.
Chemistry
1 answer:
aleksley [76]3 years ago
6 0

According to the molar ratio in the equation, for every 1 mole of HCl, 1 mole of NaCl is formed.

Thus, if 1.9 mol of HCl is used up in the reaction, 1.9 mol of NaCl is formed.

So the answer is 1.9 mol of NaCl.

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Write out the balanced chemical equation and the net ionic equation for the reaction between hydrochloric acid and sodium hydrox
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Answer:

HCl(aq) + NaOH(aq) ⇒ NaCl(aq) + H₂O(l)

H⁺(aq) + OH⁻ ⇒ H₂O(l)

Explanation:

Let's consider the balanced chemical equation (molecular equation) for the reaction between hydrochloric acid and sodium hydroxide. This is a neutralization reaction.

HCl(aq) + NaOH(aq) ⇒ NaCl(aq) + H₂O(l)

The complete ionic equation includes all the ions and the molecular species.

H⁺(aq) + Cl⁻(aq) + Na⁺(aq) + OH⁻ ⇒ Na⁺(aq) + Cl⁻(aq) + H₂O(l)

The net ionic equation includes only the ions that participate in the reaction (not spectator ions) and the molecular species.

H⁺(aq) + OH⁻ ⇒ H₂O(l)

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