When the equation BiCl3 + H2S → Bi2S3 + HCl is the coefficient of HCl will be

1 answer:

6 0

The product Bismuth (III) sulfide ( $Bi_{2}S_{3}$ ) is used as a starting material for the synthesis of other bismuth compounds. It is formed, together with an acid, from a reaction between a Bismuth (III) salt and hydrogen sulfide ( $H_{2}S$ ). In the given reaction, the Bismuth salt used in the reaction is Bismuth (III) chloride ( $BiCl_{3}$ ).

The balanced reaction of $BiCl_{3}$ and $H_{2}S$ is

$2BiCl_{3} + 3H_{2}S --> Bi_{2}S_{3}+ 6HCl$

Thus, the coefficient of HCl in the reaction is 6.

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Answer:

$1.2x10^{38}\frac{fg}{cm^3}$

Explanation:

Hello there!

In this case, for such unit conversion we need to realize that 1 kg is equal to 1000 g, 1 g is equal to 1x10⁹ and 1 mL equals 1 cm³, therefore we apply:

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