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bonufazy [111]
3 years ago
8

Combine like terms (simplify)

Mathematics
1 answer:
andre [41]3 years ago
6 0
1) 8x-13
2)19r-19s
3)8m-10n
Solve in the parentheses then label the ones with the same variable and solve those setting up the equation with variable first. Do check this I am not perfect.

Hope this helped! ;)
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A _____ is a pair of equal ratios. A) proportion B) ratio C) decimal D) percent
nekit [7.7K]
<span>In the statement "A _____ is a pair of equal ratios.", the word that completes is A, proportion. A proportion is a numerical correlation between two numbers. Frequently, these numbers can speak to an examination of things or individuals. For instance, say you strolled into a room brimming with individuals. </span>
4 0
3 years ago
Helpppppppppp Ill give a brainliest
Ludmilka [50]

Answer:

D, -1

Step-by-step explanation:

when distributing the 2 to the 2x and 5 you get the same equation as the other side.

do paranthesis first, then exponent, then multiply, add then subtract from left to right

7 0
3 years ago
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Select the correct answer.
Anni [7]

Answer:

C. vertical angles

Step-by-step explanation:

Vertical angles are a pair of opposite angles made by two intersecting lines.

6 0
3 years ago
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9[[w]^[5]]+24[[w]^[4]]+16[[w]^[3]] I need to simplify this.
kupik [55]
9w^5 + 24w^4 + 16w^3

Factor out w³.

w^3(9w^2+24w+16)

Find two numbers that multiply to equal 144 (9*16) and add to equal 24.
This would be 12 and 12.

w^3(9w^2+12w+12w

Factor.

w^3(3w(3w+4)+4(3w+4))+16)[/tex]

Simplify.

w^3(3w+4)(3w+4) = w^3(3w+4)^2

6 0
3 years ago
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A university cafeteria line in the student center is a
nirvana33 [79]

Answer:

Lamda= 4 students/min, µ= 5 students/min  

P= Lamda/µ= 4/5= 0.8

a.) Probability that system is empty= P0= 1-P= 1-0.8= 0.2

b.) Probability of more than 2 students in the system= ∑(n=3 to inf) P^n*P0= (1-P)*(1/(1-P) – (1-P) –(1-P)*P –(1-P)*P^2)= (.2)*(5-  - .2 - (.8)*.2 – (.2)*.8^2))= 0.848

Probability of more than 3 students in the system= ∑(n=4 to inf) P^n*P0= (1-P)*(1/(1-P) – (1-P) –(1-P)*P –(1-P)*P^2 – (1-P)*P^3)= 0.768

c.) W(q)= Waiting time in Queue= lamda/µ(µ- lamda)= 4/5(1)= 0.8 minutes

d.) L(q)= lamda*W(q)= 4*.8= 3.2 students

e.) L(System)= lamda/(µ-lamda)= 4 students.

f.) If another server with same efficiency as the 1st one is added, then µ= 6 sec/student= 10 students/min.

P= 4/10= 0.4

Probability that system is empty= P0= 1-.4= 0.6

W(q)= 4/10(10-4)= 0.0667 minutes

L(q)= Lamda*W(q)= 4*.0667=0.2668

L(system)= Lamda/(µ-lamda)= 4/6= .667

Step-by-step explanation:

6 0
3 years ago
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