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bonufazy [111]
3 years ago
8

Combine like terms (simplify)

Mathematics
1 answer:
andre [41]3 years ago
6 0
1) 8x-13
2)19r-19s
3)8m-10n
Solve in the parentheses then label the ones with the same variable and solve those setting up the equation with variable first. Do check this I am not perfect.

Hope this helped! ;)
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Solve x² + 11x +18=0 by factoring.
kirill [66]
-(11+sqrt(121-4*18))/2 = -(11 +sqrt(49))/2 = -9

Or

-(11-sqrt(121-4*18))/2 = -(11-sqrt(49))/2 = -2

D is the answer
5 0
2 years ago
When Sharon began shopping this morning, she had $40.00. She purchased five paperback books and had lunch. The books were all th
Tpy6a [65]

40-7 = 33

33-3.25 = 29.75

29.75/5 = 5.95 each

8 0
3 years ago
Check that x=2 and y=5 is a solution of both equations below:<br> X+2y=12<br> 3x+6y=36 *
melamori03 [73]

Answer:

yes

Step-by-step explanation:

Substitute x = 2 and y = 5 into the left side of the equations and if equal to the right side then they are a solution.

x + 2y = 2 + 2(5) = 2 + 10 = 12 ← True

3x + 6y = 3(2) + 6(5) = 6 + 30 = 36 ← True

Thus x = 2, y = 5 is a solution to both equations

7 0
3 years ago
Read 2 more answers
True or false: Polar equations can describe graphs as functions, even when their equations in the rectangular coordinate system
pshichka [43]
The statement above is true. Polar equations indeed can describe graphs as functions, even if when the equations in the rectangular coordinate system are not one of the functions. Polar equations can be graphed accurately using hands by using the Polar Coordinate System.
6 0
3 years ago
Read 2 more answers
Suppose that scores on an aptitude test are normally distributed with a mean of 100 and a standard deviation of 4.6. Scores on a
DerKrebs [107]

Answer:

<u>The correct answer is C. Felix's z-score on the aptitude test was 1.30. His z-score on the knowledge test was 2.08. Felix performed better on the knowledge test, comparatively.</u>

Step-by-step explanation:

1. Let's check all the information given to us to answer the question correctly:

Mean of the scores on the aptitude test = 100

Standard deviation of the aptitude test = 4.6

Felix's score on the aptitude test = 106

Mean of the scores on the knowledge test = 70

Standard deviation of the knowledge test = 2.4

Felix's score on the knowledge test = 75

2. Which statement best describes Felix's scores on the two tests comparatively?

Let's recall that z-score in a normal distribution, positive or negative, is the number of times of the standard deviation a certain element is from the mean. If the element is below the mean, then the z-score is negative and if it's above the mean, then the z-score is positive.

Therefore, a score of 106 on the aptitude test, will have the following z-score:

106 - 100 = 6 and it's above the mean.

Now, we calculate the z-score, using the value of the standard deviation this way:

6/4.6 = 1.30

A score of 75 on the knowledge test, will have the following z-score:

75 - 70 = 5 and it's above the mean.

Now, we calculate the z-score, using the value of the standard deviation this way:

5/2.4 = 2.08

The z-scores of Felix were 1.30 on the aptitude test and 2.08 on the knowledge test. He performed better on the aptitude test because 2.08 > 1.30, so the correct statement that best describes Felix's scores on the two tests comparatively is<u> C. Felix's z-score on the aptitude test was 1.30. His z-score on the knowledge test was 2.08. Felix performed better on the knowledge test, comparatively.</u>

6 0
3 years ago
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