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Alenkasestr [34]

2 years ago

10

How would I do this? I did the math and the slope is 3/5 and the y intercept is 76.4 but thats not one of the answers you can ch

ose.

1 answer:

pashok25 [27]2 years ago

5 0

Go over it again ! Look closely and restart. If u didn’t use pencil and paper do that.!

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Adam wishes to have $20 comma 000 available in 18 years to purchase a new car for his son as a gift for his high school graduat

wel

Adam should invest $15516 after 18 years.

<u>Explanation:</u>

Given:

Amount(18) = $20000

Rate of Interest, r = 1.41%

Time, t = 18 years

n = 365 (compounded daily)

General equation of amount that is compounded daily:

$A(t) = A_0(1 + \frac{r}{n} )^n^t$

Solving for A₀:

$A_0 = \frac{A(t)}{(1+\frac{r}{n} )^n^t}$

Substituting the values:

$A_0 = \frac{20000}{(1 + \frac{0.0141}{365})^3^6^5^X^1^8 } \\\\A_0 = \frac{20000}{1.289}\\ \\A_0 = 15516$

Therefore, Adam should invest $15516 after 18 years.

8 0

3 years ago

Please help and thank you

ziro4ka [17]

Answer:

Step-by-step explanation:

2)

x + 14 $\frac{13}{25}$ = -0.87

x + $\frac{363}{25}$ = - $\frac{87}{100}$

x + $\frac{1452}{100}$ = - $\frac{87}{100}$

x = - $\frac{87}{100}$ - $\frac{1452}{100}$

x = - $\frac{1539}{100}$

3)

x -8 $\frac{5}{6}$ = 1.5

x - $\frac{53}{6}$ = $\frac{9}{6}$

x = $\frac{9}{6}$ + $\frac{53}{6}$

x = $\frac{62}{6}$

x = $\frac{31}{3}$

4)

x - $\frac{7}{12}$ = - 7 $\frac{7}{16}$

x - $\frac{28}{48}$ = - $\frac{119}{16}$

x = - $\frac{357}{48}$ + $\frac{28}{48}$

x = - $\frac{329}{48}$

5)

$\frac{8}{9}$ - x = 6 $\frac{1}{15}$

$\frac{8}{9}$ = $\frac{91}{15}$ + x

$\frac{40}{45}$ - $\frac{273}{45}$ = x

- $\frac{233}{45}$ = x

x = - $\frac{233}{45}$

6)

-33.754 - x = 28.05

-33.754 - 28.05 = x

- 61.804 = x

x = - 61.804

7 0

3 years ago

En france en 1900 la taille moyennes des femmes etait de 1,54 m et celle des hommes de 1,66 m. Entre 1900 et 2010 ces tailles mo

frez [133]

Complete question :

En France, en 1900, la taille moyenne des femmes était de 1,54 m et celle des hommes de 1,66 m. Entre

1900 et 2010 ces tailles moyennes ont augmentées d'environ 5,55%.

Calculer, en mètres, l'arrondi au centième des tailles moyennes des femmes et des hommes en 2010.

Répondre :

Femmes = 1,63

Hommes = 1,75 m

Explication étape par étape:

Étant donné que :

Taille moyenne en 1900:

Hommes = 1,66 m

Femmes = 1,54 m

Pourcentage d'augmentation de poids d'ici 2010 = 5,55%

1 + 5,55% = 1 + 0,0555 = 1,0555

D'où,

Taille des femmes en 2010:

1,0555 * 1,54 = 1,62547 = 1,63 m

Pour la taille des hommes en 2010:

1,0555 * 1,66 m = 1,75213 = 1,75 m

3 0

3 years ago

Solve for h<br> -6 < -2h + 14

Sholpan [36]

Answer:

h<10

Step-by-step explanation:

7 0

3 years ago

I need help on this please

Misha Larkins [42]

Answer:

B. R/3

Step-by-step explanation:

5 0

3 years ago