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Ira Lisetskai [31]
3 years ago
11

When a test for steroids is given to soccer players, 98% of the players taking steroids test positive and 12% of the players not

taking steroids test positive. Suppose that 5% of soccer players take steroids. What is the probability that a soccer player who tests positive takes steroids?
Mathematics
1 answer:
anygoal [31]3 years ago
5 0

Answer:

P = 0.300 or 30%

Step-by-step explanation:

There are two possibilities for a player to test positive:

1-) He does not take steroids (95%) with a 12% chance of testing positive:

P= 0.95 x 0.12

2-) He does take steroids (5%) with a 98% chance of testing positive:

P= 0.05 x 0.98

So the probability that a player tests positive is:

P = 0.95 x 0.12 + 0.05 x 0.98 =0.163

Therefore, the probability that a soccer player who tests positive takes steroids is:

P= \frac{0.05 * 0.98 }{0.163}\\P=0.300

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Answer:

Answer:

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Step-by-step explanation:

This equation is just basic alegebra.  First, combine like terms to get

9 - n = 8n.  (Because 3 - 3 = 0, and -4n + 3n = -n.)  Now the equation is much simpiler;  add n to both sides to get 9 = 9n.  Divide 9 by both sides to get that n = 1.  

You can check your answer by plugging 1 in for n.  

9 - 4(1) + 3(1) = 8(1) + 3 - 3

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Therefore, n is proven to equal 1.  

Hope this is helpful kid sorry i went very far yesterday hope you can forgive me but Anyways here it is <3

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