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Ira Lisetskai [31]
3 years ago
11

When a test for steroids is given to soccer players, 98% of the players taking steroids test positive and 12% of the players not

taking steroids test positive. Suppose that 5% of soccer players take steroids. What is the probability that a soccer player who tests positive takes steroids?
Mathematics
1 answer:
anygoal [31]3 years ago
5 0

Answer:

P = 0.300 or 30%

Step-by-step explanation:

There are two possibilities for a player to test positive:

1-) He does not take steroids (95%) with a 12% chance of testing positive:

P= 0.95 x 0.12

2-) He does take steroids (5%) with a 98% chance of testing positive:

P= 0.05 x 0.98

So the probability that a player tests positive is:

P = 0.95 x 0.12 + 0.05 x 0.98 =0.163

Therefore, the probability that a soccer player who tests positive takes steroids is:

P= \frac{0.05 * 0.98 }{0.163}\\P=0.300

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<span>we have that

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</span>∛[27(cos 330° + i sin 330°)]

we know that
e<span>^(ix)=cos x + isinx
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3∛[(e^(i110°)³)]--------> 3e^(i110°)-------------> 3[cos 110° + i sin 110°]

z1=3[cos 110° + i sin 110°]

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<span>therefore
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z2=3[cos ((110°+120°) + i sin (110°+120°)]------ > 3[cos 230° + i sin 230°]

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<span>
the answer is 

</span>z1=3[cos 110° + i sin 110°]<span>

</span>z2=3[cos 230° + i sin 230°]

z3=3[cos 350° + i sin 350°]<span>

</span>
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