Answer:
(7, 24, 26)
Step-by-step explanation:
A Pythagorean triple must have an odd number of even numbers. The triple (7, 24, 26) is not a Pythagorean triple.
_____
<em>Additional comment</em>
For an odd integer n, a triple can be formed as ...
(n, (n²-1)/2, (n²+1)/2)
That is, the following will be Pythagorean triples.
- (3, 4, 5)
- (5, 12, 13)
- (7, 24, 25)
- (9, 40, 41)
- (11, 60, 61)
Another series involves even numbers and numbers separated by 2:
(2n, n²-1, n²+1)
- (8, 15, 17)
- (12, 35, 37)
- (16, 63, 65)
In this list, if n is not a multiple of 2, the triple will be a multiple of one from the odd-number series.
It is a good idea to remember a few of these, as they tend to show up in Algebra, Geometry, and Trigonometry problems.
Answer:
9^8
Step-by-step explanation:
9²•9⁶ = 9^(2+6) = 9^8
Answer:
10,9.75,9.5,9.25,9, 8.75 , 8.5, 8.25, 8...
Step-by-step explanation:
Subtract 0.25 from each to find the next number
Answer:
<em>0</em> is the probability that a randomly selected student plays both a stringed and a brass instrument.
Step-by-step explanation:
Given that:
Number of students who play stringed instruments, N(A) = 15
Number of students who play brass instruments, N(B) = 20
Number of students who play neither, N(
)' = 5
<u>To find:</u>
The probability that a randomly selected students plays both = ?
<u>Solution:</u>
Total Number of students = N(A)+N(B)+N(
)' =15 + 20 + 5 = 40
(As there is no student common in both the instruments we can simply add the three values to find the total number of students)
As per the venn diagram, no student plays both the instruments i.e.

Formula for probability of an event E can be observed as:


So, <em>0</em> is the probability that a randomly selected student plays both a stringed and a brass instrument.