Answer:
the mean in set B is equal to the mean in set A (option C)
Question:
The question is incomplete as the answer choices were not given.Let's consider the following question:
Data set A is {30, 45, 32, 50, 33, 40, 44, 32}. Data set B is {28, 43, 30, 48, 35, 42, 46, 34}. which statement best compares the two data sets?
a) median for set A is equal to the median for set B
b) Range for set A is greater than range for set B
c) The mean in set B is equal to the mean in set A
Step by step explanation:
We can describe a data set using four ways:
Center, spread, shape and unusual features.
Let's consider the center and spread.
Center: This is the median of the distribution.
Spread: This is the variation of the data set. If the range is wide, the spread is larger and If the range is small, the spread is smaller.
Rearranging the data set:
A = {30, 32, 32, 33, 40, 44, 45, 50}
B = {28, 30, 34, 35, 42, 43, 46, 48}
From the data:
The median for set A = (33+40)/2 = 73/2= 36.5
The median for set B = (35+42)/2 = 77/2= 38.5
Range = highest value - lowest value
The data ranges from 30 to 50 (range = 20) for A
The data ranges from 28 to 48 (range = 20) for B
Mean for set A = (30+32+32+33+40+4445+50)/8 = 306/8 = 38.25
Mean for set B = (28+30+34+35+42+43+46+48)/8= 306/8 = 38.25
In both data set the mean is equal to 38.25.
Therefore the statement that best compares the two data sets is the mean in set B is equal to the mean in set A (C)
yards, width 
yards and height of 4 yards will be:
cubic yards