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3 years ago

What is the solution to the equation x÷8−6=3?

Mathematics

1 answer:

Charra [1.4K]3 years ago

8 0

Answer: D. x=72

Step-by-step explanation:

With the equation x/8-6=3 we can start solving by first moving the "-6"

x/8-6(<u>+6)</u>=3(+6)

x/8=9 <-- Rewrite equation after adding "6" to both sides

x/8(*8)=9(*8) <--- Multiply both sides by 8

x=72 <-- After multiplying, solution is found

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The value of y varies directly with x. When y = 75, x = ½ . What is the value of y when x is 2 ¼ ? A. 168.75 C. 66.67 B. 16.67 D

lora16 [44]

Answer:

Step-by-step explanation:

The value of y varies directly with x. When y = 75, x = ½ . What is the value of y when x is 2 ¼ ? A. 168.75 C. 66.67 B. 16.67 D. 337.5

y ∝x

y = kx

k = y/x

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3 years ago

Jackie is reading a 252 page novel for her summer reading project. On Monday she reads 4/8 of the novel. On Tuesday she reads 28

natima [27]

So far, Jackie has read 217 pages

In order to determine the total number of pages Jackie read, we would have to determine the number of pages she read each day and add these pages together

Number of pages she read on Monday = $\frac{4}{8}$ x 252 = 126 pages
Number of pages she read on Tuesday = 28 pages
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A similar question was solved here: brainly.com/question/24708342?referrer=searchResults

5 0

3 years ago

5. What is the equation of the tangent line to the circle x^2+y^2=1 through the point (6,0)?

notka56 [123]

Answer:

There is no tangent line of the given circle at (6, 0).

Step-by-step explanation:

Given equation of the circle,

$x^2 + y^2 = 1$

∵ equation of a circle is $(x-h)^2 +(y-k)^2 = r^2$ ,

Where, (h, k) is the center of the circle and r is the radius,

By comparing,

Center of the given circle = (0, 0),

Radius of the circle = 1 unit

Now, check whether point (6, 0) lie on the circle,

if x = 6, $6^2 + y^2 = 1$

$36 + y^2 = 1$

$y^2 = 1- 36$

$y= i\sqrt{35}\neq 0$

i.e., (6, 0) does not lie on the circle,

Hence, there is no tangent line of the given circle at (6, 0).

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3 years ago

The two perpendicular lines of a coordinate plane that intersect at the origin (singular: axis)

Svetach [21]

3. Axes
That’s what it should be

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3 years ago

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On a coordinate plane, a dashed straight line has a positive slope and goes through (negative 1, negative 1) and (0, 1). Everyth

HACTEHA [7]

Answer:

y > 2x + 1

Step-by-step explanation:

The equation of a straight line is

y = mx + b

Your graph looks like the diagram below.

Calculate the slope of the line:

$\begin{array}{rcl}m & = & \dfrac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\ & = & \dfrac{1 - (-1) }{0 - (-1)}\\\\& = & \dfrac{2}{1}\\\\& = & \mathbf{2} \\\end{array}$

That eliminates Options B and D.

The y intercept is at y = 1.

That eliminates Option A.

The only inequality that fits is

y > 2x + 1

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3 years ago

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