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lorasvet [3.4K]
3 years ago
15

Alex is training for his school's Jog-A Thon and needs to run at least 1 mile per day. If Alex runs to his grandma's house, whic

h is 5/8 of a mile away and then to his friend Justin's house which is 1/2 mile away, he will have trained enough for the day? Group of answer choices True False
Mathematics
1 answer:
Sholpan [36]3 years ago
5 0
True. 5/8 + 1/2 is. 9/8. Yes he have trained enough, even more than a mile
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Can someone please help me with math.
mrs_skeptik [129]

Option c. is the correct answer.

3 0
2 years ago
3cis(5pi/4) in polar form
madreJ [45]
Rectangular form:
z = -2.1213203-2.1213203i

Angle notation (phasor):
z = 3 ∠ -135°

Polar form:
z = 3 × (cos (-135°) + i sin (-135°))

Exponential form:
z = 3 × ei (-0.75) = 3 × ei (-3π/4)

Polar coordinates:
r = |z| = 3 ... magnitude (modulus, absolute value)
θ = arg z = -2.3561945 rad = -135° = -0.75π = -3π/4 rad ... angle (argument or phase)

Cartesian coordinates:
Cartesian form of imaginary number: z = -2.1213203-2.1213203i
Real part: x = Re z = -2.121
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8 0
2 years ago
A function, f(x)=4x+5, has a domain 0<=x<=50. What is the range? How do you do this??
babunello [35]

Step-by-step explanation:

remember the domain is the interval or set of valid input (x) values. the range is the interval or set of the valid result (y) values.

so, the given domain tells us the interval to look at.

what are the functional values of the function between 0 and 50 ?

since the function is continuous (there are no gaps) in this interval, we can safely assume that all values between f(0) and f(50) are valid y values.

f(0) = 4×0 + 5 = 5

f(50) = 4×50 + 5 = 205

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3 0
2 years ago
the weight of a bucket is 33/2 kg. if 1/4 of the bucket contains water weighing 21/4 kg , determine the weight of empty bucket
Sauron [17]

Answer:

15.733kg

Step-by-step explanation:

33.2 - 21.4 = 11.8

3/4 of the bucket empty is 11.8kg.

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7 0
2 years ago
7.
Svetlanka [38]

Answer:

D. y ≥ 2x – 2

Step-by-step explanation:

Graph the inequality by finding the boundary line, then shading the appropriate area.

y ≥ 2 x + 2

Graph the inequality by finding the boundary line, then shading the appropriate area.

y ≥ − 2 x + 2

Graph the inequality by finding the boundary line, then shading the appropriate area.

y ≤ 2 x − 2

Graph the inequality by finding the boundary line, then shading the appropriate area.

y ≥ 2 x − 2

5 0
3 years ago
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