Answer:
4m
Step-by-step explanation:
0.8x5=4
<h3>Answers:</h3>
- (a) The function is increasing on the interval (0, infinity)
- (b) The function is decreasing on the interval (-infinity, 0)
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Explanation:
You should find that the derivative is entirely negative whenever x < 0. This suggests that the function f(x) is decreasing on this interval. So that takes care of part (b).
The interval x < 0 is the same as -infinity < x < 0 which then translates to the interval notation (-infinity, 0)
Similarly, you should find that the derivative is positive when x > 0. So the function is increasing on the interval (0, infinity)
Answer:
x = 3.25
y =4.75
Step-by-step explanation:
In order to Solve the following system of equations below algebraically using substitution method we say that;
let;
8x - 4y = 7
..................... equation 1
x + y = 8.......................... equation 2
from equation2
x + y = 8.......................... equation 2
x = 8 - y.............................. equation 3
substitute for x in equation 1
8x - 4y = 7
..................... equation 1
8(8-y) - 4y = 7
64-8y-4y=7
64-12y=7
collect the like terms
64-7 = 12y
57= 12y
divide both sides by the coefficient of y which is 12
57/12 = 12y/12
4.75 = y
y =4.75
put y = 4.75 in equation 3
x = 8 - y.............................. equation 3
x = 8 -4.75
x = 3.25
to check if your answer is correct, put the value of x and y in either equation 1 or 2
from equation 2
x + y = 8.......................... equation 2
3.25 + 4.75 =8
8=8.................... proved
So,
First, I'd like to note that it is required to show work. You shouldn't need to ask for steps.
7(2p + 3) - 8 = 6p + 29
Distribute
14p + 21 - 8 = 6p + 29
Collect Like Terms
14p + 13 = 6p + 29
Subtract 6p from both sides
8p + 13 = 29
Subtract 13 from both sides
8p = 16
Divide both sides by 8
p = 2
Check
7(2(2) + 3) - 8 = 6(2) + 29
Simplify inside the parentheses first.
7(4 + 3) - 8 = 6(2) + 29
7(7) - 8 = 6(2) + 29
Now, distribute.
49 - 8 = 12 + 29
Collect Like Terms
41 = 41 This checks.
S = { 2 }
What are the options on top take a picture of those then I will be able to help you
