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OlgaM077 [116]
3 years ago
14

HELP PLEASE IF YOU CAN ONLY 1 QUESTION

Mathematics
2 answers:
Brums [2.3K]3 years ago
7 0

Answer:

divide both sides by 7

Step-by-step explanation:

you want to isolate d by its self

WINSTONCH [101]3 years ago
7 0

Answer:

The answer to your question is to Divide both sides by 7

Step-by-step explanation:

Once you have the equation          7d = 49

you have to divide both sides by seven as is shown        7/7 d = 49/7

After that, solve the division          d = 7

And that is the result of the equation

The other choices are not possible answers to this question.

You might be interested in
Is a relation always a function? Is a function always a relation? Explain.
katen-ka-za [31]

A function is always a relation but relation is not always a function

<u>Solution:</u>

Given that, we have to explain Is a relation always a function and is a function always a relation

Note that both functions and relations are defined as sets of lists.  

In fact, every function is a relation. However, not every relation is a function.  A relation from a set X to a set Y is called a function if each element of X is related to exactly one element in Y.

That is, given an element x in X, there is only one element in Y that x is related to.

For example, consider the following sets X and Y. Let me give you a relation between them that is not a function;

X = { 1, 2, 3 }

Y = { a , b , c, d }

Relation from X to Y : { (1,a) , (2, b) , (2, c) , (3, d) }

This relation is not a function from X to Y because the element 2 in X is related to two different elements, b and c

Relation from X to Y that is a function: { (1,d) , (2,d) , (3, a) }

This is a function since each element from X is related to only one element in Y. Note that it is okay for two different elements in X to be related to the same element in Y. It's still a function, it's just not a one-to-one function.

So, we can say that function is a type of relation.

Which means whatever a function occurs, it will be a relation from one set to other.

But when a relation occurs it may be a function but need not be always a function.

Hence, a function is always a relation but relation is not always a function.

8 0
3 years ago
PLEASE HELPPP<br> ONG ILL GIVE YOU ALL MYPOINTS JUST HELP
vampirchik [111]
The answer is 13 hope I helped
5 0
2 years ago
Read 2 more answers
Please help. Write as a single logarithm, a) log(13)+log(4) b) log(small 5)(14)-log(small 5)(2)
dsp73

Answer:

a) \log 52

b) \log_57

Step-by-step explanation:

Use logarithm properties:

\log_ab+\log_ac=\log_a(b\cdot c)\\ \\\log_ab-\log_ac=\log_a\dfrac{b}{c}

Then

a) \log 13+\log 4=\log 13\cdot 4=\log 52

b) \log_514-\log _52=\log _5\dfrac{14}{2}=\log _57

7 0
3 years ago
19 – 5x = 9(1+x) solve
Maurinko [17]

\Large\boxed{\tt Answer:~x=\frac{5}{7} }

\tt Step-by-step~explanation:

Remember: PEMDAS - Parentheses, exponents, multiply/divide, add/subtract

Distribute: 9(1+x) = 9+9x

19 - 5x = 9 + 9x

Add 5x to both sides of the equation and subtract 9 from both sides.

19 - 5x + (5x) = 9 + 9x + (5x)

19 - (9) = 9 - (9) + 14x

10 = 14x

Divide both sides by 14 to get the variable on its own.

10/14 = 14x/14

10/14=x

5/7 = x

7 0
3 years ago
Read 2 more answers
Simplify<br> Rewrite the expression in the form 6^n
prisoha [69]

Answer:

6^{3}

Step-by-step explanation:

6^4/6^1

6^(4-1)

=6^3

6 0
2 years ago
Read 2 more answers
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