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STatiana [176]
3 years ago
5

Explain why domain restrictions for inverse trigonometric functions are necessary

Mathematics
1 answer:
lakkis [162]3 years ago
8 0

Step-by-step explanation:

Remember that any function pairs each <em>x</em> value with <u>exactly one</u> <em>y</em> value.  No <em>x</em> can have more than one <em>y</em> corresponding to it.

Example: when you take the points on the function y = sin x and reverse their coordinates (switch the <em>x</em>'s and <em>y</em>'s), you get the blue squiggly line (see graph) that goes up and down the <em>y</em>-axis.  For instance, a point on the graph of y = sin x is (pi/2, 1) and this becomes the point (1, pi/2) on the blue wave.

The blue wave is <u>not</u> a function!  It fails the Vertical Line Test miserably. Each <em>x</em> corresponds to an infinite number of <em>y</em>'s.

Going back to y = sin x, you restrict its domain (all real numbers) to a set of numbers that will prevent the inverse from "doubling back" on itself--each <em>x</em> will correspond to only one <em>y</em>.

There are standard ways of doing this for each trigonometric function.  For the sine function, you restrict its domain to the interval [-pi/2, pi/2}.  When the coordinates of the restricted graph are switched, you get the red graph, which is a function, the inverse sine function.

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Andre45 [30]

Answer:

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Step-by-step explanation:

We can interpret the question to have two equation which can be solve simultaneously

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Substitute the (3) into eqn(1)

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a= 2+5/2

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