Let a checked bag = x
Since they are of the same weight
The two checked bags = x+x=2x
Another backpack that weighs 4kg
Total baggage =35
:- 2x + 4 = 35
2x = 35-4
2x = 31
The two checked bag weighs 31
Therefore the weight of one =15.5kg
Answer: Expected number of tests = 5.013
Step-by-step explanation:
Define random variable X that marks the number of tests required for some certain
group. Observe that if the test is negative for all the people (which has probability 0.95), we make one and only one test. If some of the people is tested positive, we make ten additional tests for every person in that group separately. Hence, the expected number of tests will be for if they are all negative (1 test) and the case of at least one person testing positive (11 tests).
That Is,
E(X) = 1(0.95^10) + 11(1 - (0.95^10))
E(X) = 0.5987 + 4.414 = 5.013
Answer:
The correct option is (A). The first equation is for sample data; the second equation is for a population.
Step-by-step explanation:
According to the scenario, the following would be represented as a sample and the population
Y with caret = b0 + b1x = sample
and
y = b0 + b1x = population
It is because if we considered the population than the expected value would be nearest and there is no need to determine the b0 and b1 value again. But in the case of the sample, the reestimation of the values would be determined again and again
Therefore the correct option is A.
Answer:
-56
Step-by-step explanation: