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Lyrx [107]
3 years ago
8

Write an equation of the sine function with amplitude 9 period 3 pi

Mathematics
1 answer:
Alchen [17]3 years ago
6 0
The a in front of Sin is the amplitude and the period is 2pi/k.
To get a period of 3pi, set up an equation. 3pi = 2pi/k and solve for k.
3pi = 2pi/k
Multiply k on both sides.
k * 3pi = 2pi
Divide both sides by 3pi
k = 2pi/3pi; k = 2/3

y = 9Sin(2/3)x
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Answer:

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let Ani age be X

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5 0
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Assoli18 [71]

Answer:

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