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swat32
3 years ago
15

What is 9plus9plus3plus7plus4plus6plu4plus5plus7plus3plus6

Mathematics
2 answers:
crimeas [40]3 years ago
8 0
9 + 9 + 3 + 7 + 4 + 6 + 4 + 5 + 7 + 3 + 6 = 63
aalyn [17]3 years ago
4 0
9+9+3+7+4+6+4+5+7+3+6= 63
Its simple addition, just do it one number at a time :)

Hope I helped! <3
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simplify 4 square root of 2 end root plus 7 square root of 2 end root minus 3 square root of 2. 2 square root of 8 8 square root
Alex787 [66]

<u>Answer</u>

8√2


<u>Explanation</u>

Simply: 4√2 + 7√2 - 3√2

Let √2 = x

4√2 + 7√2 - 3√2 = 4x + 7x - 3x

                             = 11x - 3x

                             = 8x

Substituting x with √2

4√2 + 7√2 - 3√2 = 8√2

4 0
3 years ago
Read 2 more answers
Oscar is having a spaghetti party for his hiking group the night before his trip. He expects 12 members. Oscar knows that a 16oz
Reil [10]
4 and a half cups of pasta for the party
4 0
3 years ago
What is the volume of this solid figure made with cubes
Nana76 [90]

Answer:

15

Step-by-step explanation:

three times five = fifteen and height is 1

5 0
3 years ago
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Suppose a batch of metal shafts produced in a manufacturing company have a standard deviation of 1.5 and a mean diameter of 205
Crank

Answer:

P(205-0.3=204.7

z=\frac{204.7-205}{\frac{1.5}{\sqrt{79}}}=-1.778

z=\frac{205.3-205}{\frac{1.5}{\sqrt{79}}}=1.778

So we can find this probability:

P(-1.778

And then since the interest is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.3 inches using the complement rule we got:

P = 1-0.9243 = 0.0757

Step-by-step explanation:

Let X the random variable that represent the diamters of interest for this case, and for this case we know the following info

Where \mu=205 and \sigma=1.5

We can begin finding this probability this probability

P(205-0.3=204.7

For this case they select a sample of n=79>30, so then we have enough evidence to use the central limit theorem and the distirbution for the sample mean can be approximated with:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{\bar x-\mu}{\frac{\sigma}{\sqrt{n}}}

And we can find the z scores for each limit and we got:

z=\frac{204.7-205}{\frac{1.5}{\sqrt{79}}}=-1.778

z=\frac{205.3-205}{\frac{1.5}{\sqrt{79}}}=1.778

So we can find this probability:

P(-1.778

And then since the interest is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.3 inches using the complement rule we got:

P = 1-0.9243 = 0.0757

6 0
3 years ago
Here is a easy one :) <br> what is 100 divided -10?
hammer [34]
-10 is the answer... lol
8 0
3 years ago
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