note that gradient = 
at x = a
calculate for each pair of functions and compare gradient
(a)
= 2x and = - 1
at x = 4 : gradient = 8 and - 1 : 8 > - 1
(b)
= 2x + 3 and = - 2
at x = 2 : gradient = 7 and - 2 and 7 > - 2
(c)
= 4x + 13 and = 2
at x = - 7 : gradient = - 15 and 2 and 2 > - 15
(d)
= 6x - 5 and = 2x - 2
at x = - 1 : gradient = - 11 and - 4 and - 4 > - 11
(e)
y = √x = 
= 1/(2√x) and = 2
at x = 9 : gradient = 
and 2 and 2 >
Answer:
B
Step-by-step explanation:
First, move like terms on one side. Next, add them and divide. See the attachment for solution.
You said -x + 8 > 6
Subtract 8 from each side: -x > -2
Add 'x' to each side: 0 > -2 + x
Add 2 to each side: 2 > x
Now, test the choices:
A). Can 'x' be 4 ?
No. 2 is not greater than 4 .
B). Can 'x' be 1 ?
Yes. 2 is greater than 1 .
C). Can 'x' be 2 ?
No. 2 is not greater than 2 .
D). Can 'x' be 15 ?
No. 2 is not greater than 15 .
